<h3>
Answer: g(x) = (-2/3)*x^2</h3>
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Work Shown:
f(x) = x^2
g(x) = a*f(x) for some constant 'a' since g(x) is a scaled version of f(x).
The value of 'a' vertically stretches f(x) upward if a > 0
If 'a' is negative, then we have a reflection going on as shown in the diagram.
We want (x,y) = (3,-6) to be on the graph of g(x). This means g(3) = -6
If we plugged x = 3 into f(x), we get
f(x) = x^2
f(3) = 3^2
f(3) = 9
So,
g(x) = a*f(x)
g(3) = a*f(3) ... replace x with 3
g(3) = a*9 ... replace f(3) with 9 since f(3) = 9
-6 = a*9 ... replace g(3) with -6 since g(-3) = -6
9a = -6
a = -6/9
a = -2/3
Therefore, this means
g(x) = a*f(x)
g(x) = (-2/3)*f(x)
g(x) = (-2/3)*x^2
Answer:
-5
Step-by-step explanation:
Yes it is an imaginary number.
Answer:
See below
Step-by-step explanation:
<u>Given:</u>
- f(x)= { 3x+1, if −9 < x ≤ −2
- f(x)= {−5, if. −2 < x ≤ 1
- f(x)= { x−6, if 1 < x < 7
<u>Combination of domain for the function is the following union:</u>
- (-9, 2]∪ (-2, 1]∪(1, 7) = (-9, 7)
<u>Group of answer choices:</u>
The domain is the depth interval (−26, 1).
- incorrect as (-26, -9) interval is not covered in given function
The domain is the depth interval (−9, 1].
The domain is the set of times −9 < x < −2, −2 < x < 1, and 1 < x < 7.
- incorrect as doesn't include x = -2 and x = 1
The domain is the time interval (−9, 7).
- This is correct as it is same with the domain set we got above.
