Which statement is correct about the product of 323 and 109?

A cutting tool fails due to flank wear while machining. It is observed that the tool life at a cutting speed of 160 m/min is 5 m

Ahat [919]

Answer:

The answer is:

30 minutes.

Step-by-step explanation:

We are given the following information:

at 160 m/min, tool life = 5 min.

at 120 m/min, tool life = 17 min.

This means that as the speed reduced from 160 m/min to 120 m/min, the tool life increased from 5 min. to 17 min, hence the difference between the changes are:

speed = 160 - 120 = 40 m/min

tool life = 17 - 5 = 12 min.

Therefore, it can be concluded that a change of speed of 40 m/min, increases the tool life by 12 min.

40 m/min = 12 min

∴ 1 m/min = 12/40 min.

∴ 100 m/min = 12/40 × 100 = 0.3 × 100 =30 min.

8 0

2 years ago

P(x) = 5x4 + 7x3 – 2x2 – 3x + c<br> C=

Ghella [55]

Answer:

c=Px−5x4−7x3+2x2+3x

Step-by-step explanation:

Solve for

c

by simplifying both sides of the equation, then isolating the variable.

5 0

2 years ago

The bike store marks up the wholesale cost of all of the bikes they sell by 30%.

aev [14]

Answer:

A ) The money which Andre pay for the bike is $ 67.30

B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

Given as :

The wholesale cost or market price of the bike = m.p = $ 96.15

A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 30 % = 1 - $\dfrac{s. p }{m . p}$

or, $\dfrac{30 }{100}$ = 1 - $\dfrac{s. p }{96.15}$

Or, $\dfrac{s. p }{96.15}$ = 1 - $\dfrac{30 }{100}$

or, $\dfrac{s. p }{96.15}$ = $\dfrac{100 - 30 }{100}$

Or, $\dfrac{s. p }{96.15}$ = $\dfrac{70}{100}$

Or, s. p = $\dfrac{70}{100}$ × 96.15

∴ s.p = $ 67.305

So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30 . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 20 % = 1 - $\dfrac{s. p' }{m . p}$

or, $\dfrac{20 }{100}$ = 1 - $\dfrac{s. p' }{96.15}$

Or, $\dfrac{s. p' }{96.15}$ = 1 - $\dfrac{20 }{100}$

or, $\dfrac{s. p' }{96.15}$ = $\dfrac{100 - 20 }{100}$

Or, $\dfrac{s. p' }{96.15}$ = $\dfrac{80}{100}$

Or, s. p' = $\dfrac{80}{100}$ × 96.15

∴ s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92 . Answer

7 0

2 years ago

12 girls are having a sleepover at a house, the food there can last them for 10 days. If 3 more girls came over, how long will f

FrozenT [24]

Answer:

The answer is 8

Step-by-step explanation:

12*10=120 120/15=8

8 0

2 years ago

Which polynomial expression represents a sum of cubes? (6 – s)(s2 + 6s + 36) (6 + s)(s2 – 6s – 36) (6 + s)(s2 – 6s + 36) (6 + s)

Nadusha1986 [10]

Answer:

Option 3 is correct that is $(6+s)(s^2-6s+36)$

Step-by-step explanation:

We have general formula for sum of cube which is

$a^3+b^3=(a+b)(a^2+b^2-ab)$

Here, we have a=s and b=6

on substituting the values in the formula we will get

$6^3+s^3=(6+s)(s^2+6^2-6s)$

After simplification we will get

$6^3+s^3=(6+s)(s^2+36-6s)$

After rearranging the terms we will get

$6^3+s^3=(6+s)(s^2-6s+36)$ which exactly matches option 3 in the given options.

Therefore, option 3 is correct that is $(6+s)(s^2-6s+36)$

4 0

2 years ago

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Which statement is correct about the product of ​323​ and ​109​?

Which statement is correct about the product of 323 and 109?