Factor X^2-5x-24 Please write in normal numbers like -2,1

Health club A charges $60 yearly enrollment fee and $2 per visit. Health club B charges $20 yearly enrollment fee and &4 per

Nookie1986 [14]

Answer:

With 20 visits in one year the cost of the clulbs are equal.

Step-by-step explanation:

On the club A the amount paid in function of the number of visits can be expressed as bellow:

cost = 60 + 2*visits

On the club B the amount paid in function of the number of visits can be expressed as:

cost = 20 + 4*visits

In order for the cost to be the same we must find a value of visits that makes them equal, so we have:

60 + 2*visits = 20 + 4*visits

2*visits - 4*visits = 20 - 60

-2*visits = -40

visits = 20

With 20 visits in one year the cost of the clulbs are equal.

5 0

4 years ago

Question 2

Sedbober [7]

Answer:

false, 1 is not the smallest uneven prime number as it is not a prime number, prime numbers have 2 and only 2 factors whereas 1 only has 1 factor, as well as this, you can have negative prime numbers

4 0

3 years ago

Read 2 more answers

Given two points on a line determine (a) the slope of the line using m=y^2-y^1/x^2-x^1 and (b) the equation of the line in y= mx

Anni [7]

(2,5) (3,-) do not quote me on it but I think that’s wrong

3 0

3 years ago

Read 2 more answers

What property is n/6=3 n=18? commutative?

Brilliant_brown [7]

I hope this helps you 6.n/6=6.3 n=18

6 0

4 years ago

A simple random sample of size equals 49 is obtained from a population with mu equals 84 and sigma equals 14. (a) Describe the

Gelneren [198K]

Answer:

(a) The sampling distribution of $\bar X$ is given by;

$\bar X$ ~ Normal ( $\mu =84, s = \frac{\sigma}{\sqrt{n} } =\frac{14}{\sqrt{49} }$ )

(b) P( $\bar X$ > 87.8) = 0.0287

Step-by-step explanation:

We are given that a simple random sample of size equals 49 is obtained from a population with mu equals 84 and sigma equals 14.

Let $\bar X$ = sample mean

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 84

$\sigma$ = standard deviation = 14

n = sample size = 49

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) The sampling distribution of $\bar X$ is given by;

$\bar X$ ~ Normal ( $\mu =84, s = \frac{\sigma}{\sqrt{n} } =\frac{14}{\sqrt{49} }$ )

(b) Probability of $\bar X$ greater than 87.8 is given by = P( $\bar X$ > 87.8)

P( $\bar X$ > 87.8) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{87.8-84}{\frac{14}{\sqrt{49} } }$ ) = P(Z > 1.90) = 1 - P(Z $\leq$ 1.90)

= 1 - 0.9713 = 0.0287

The above probability is calculated by looking at the value of x = 1.90 in the z table which has an area of 0.9713.

5 0

4 years ago