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bearhunter [10]
3 years ago
9

Write two inequalities to compare -2 and -18

Mathematics
1 answer:
QveST [7]3 years ago
8 0

Step-by-step explanation:

here's the answer to your question

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What is the difference of (4-5y)-2(3.5y-8)?
Dafna1 [17]
<span>20 - 12y Simplify parentheses: 4 - 5y - 7y + 16 Combine similar terms: 4 + 16 - 5y - 7y Simplify: 20 - 12y</span>
7 0
4 years ago
How can we classify the following shape?​
DerKrebs [107]

Answer:

Parallelogram

Step-by-step explanation:

Parallelograms have 2 sets of parallel sides, hence the name.

3 0
3 years ago
3.4=21 2.5=7. 4.4=؟​
Licemer1 [7]

Answer:

32

Step-by-step explanation:

From the given values

The possible logic could be

if x.y is given

then it is equal to=\frac{(x+y)\times x}{y-3}

For 1st example

3.4=\frac{(3+4) \times 3}{4-3} =\frac{21}{1} =21

For 2nd example

2.5=\frac{(2+5) \times 2}{5-3} =\frac{7 \times 2}{2} =7

⇒4.4=\frac{(4+4)\times 4}{4-3} =32

4 0
4 years ago
If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?
Agata [3.3K]
<h3>Given</h3>

A geometric sequence such that ...

a_2=-2\quad\text{and}\quad a_5=16

<h3>Find</h3>

a_{14}

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192

7 0
3 years ago
Please help asap!!!!!!!! Number 2 and 3
romanna [79]

Answer:

Step-by-step explanation:

2)  r = 16/2 = 8 cm

Area of top and bottom = 2*πr²

                                        = 2 * 3.14 * 8 * 8

                                       = 401.92 cm²

Midlle part = h * πd

                 = 6 * 3.14 * 16

                = 301.44 cm²

Total = 401.92 + 301.44

        =        703.36 cm²

3) Area of front and back = 2* \frac{1}{2}*b * h\\

                                         = 2*\frac{1}{2} * 3 * 4\\\\= 12 cm^{2}

Area of bottom = length * breadth

                           = 12* 3

                          = 36 cm²

Area of left =  12 * 4

                  = 48 cm²

Area of right = 12 * 5 = 60 cm²

Total = 12 + 36 + 48 + 60 = 156cm²

7 0
3 years ago
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