Hi i think you forgot to attach the picture
There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
Answer:
Step-by-step explanation:
If you meant to type x+1<21, then we simplify this inequality by subtracting 1 from both sides, ending up with x < 20.
I do not recognize what your "4" represents.
Answer:
Step-by-step explanation:

Answer:
this only goes to the thousanths.
Step-by-step explanation: