All categories

3 years ago

I need help plssssssssss

Mathematics

1 answer:

Alex787 [66]3 years ago

4 0

Answer:

answer is provided below

Step-by-step explanation:

5 ----> constant

+ ------> operator

2 ------> coefficient

2x ------> variable term

x --------> variable

Hope the above solution helps

You might be interested in

How do you solve this question?

Setler [38]

Find out what the variable.

7 0

4 years ago

Please help! Will give all my points! Due in 30 mins!

Blababa [14]

Answer:

WELP 30 mins passed

Step-by-step explanation:

7 0

3 years ago

A random sample of 250 students at a university finds that these students take a mean of 15.3 credit hours per quarter with a st

SpyIntel [72]

Answer: $15.3\pm0.198$

(15.102, 15.498)

Step-by-step explanation:

The formula to find the confidence interval $(\mu)$ is given by :-

$\overline{x}\pm z_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

, where n is the sample size

$s$ = sample standard deviation.

$\overline{x}$ = Sample mean

$z_{\alpha/2}$ = Two tailed z-value for significance level of $\alpha$ .

Given : Confidence level = 95% = 0.95

Significance level = $\alpha=1-0.95=0.05$

$s= 1.6$

$\overline{x}=15.3$

sample size : n= 250 , which is extremely large ( than n=30) .

So we assume sample standard deviation is the population standard deviation.

thus , $\sigma=1.6$

By standard normal distribution table ,

Two tailed z-value for Significance level of 0.05 :

$z_{\alpha/2}=z_{0.025}=1.96$

Then, the 95% confidence interval for the mean credit hours taken by a student each quarter :-

$15.3\pm (1.96)\dfrac{1.6}{\sqrt{250}}\\\\ =15.3\pm 0.19833\\\\=\approx15.3\pm0.198\\\\=(15.3-0.198,\ 15.3+0.198)=(15.102,\ 15.498)$

Hence, the mean credit hours taken by a student each quarter using a 95% confidence interval. =(15.102, 15.498)

5 0

4 years ago

The relationship between time and distance remaining on a 3 mile walk for someone walking at a rate of 2miles per hour

Maksim231197 [3]

Answer:

$Remaining\ distance=3-2t\ \ \ \ \ \ \ \ \ (where\ t\ is\ time)$

Step-by-step explanation:

$Total\ distance=3\ mile\\\\speed=2\ miles/hour\\\\Time=t\\\\In\ t\ hours\ distance\ covered=velocity\times time=2\times t=2t\\\\Remaining\ distance=total\ distance-distance\ covered\\\\Remaining\ distance=3-2t$

6 0

3 years ago

Please help.<br> I need the answer asap

Ymorist [56]

Do u still need the answer its been 2 weeks now!

4 0

3 years ago

I need help plssssssssss​

I need help plssssssssss