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Evgesh-ka [11]
3 years ago
8

6

Mathematics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

12 less than or equal to 2

Step-by-step explanation:

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Use the figure to identify each pair of angles as complementary angles, supplementary angles, vertical angles, or none of these.
maxonik [38]

(a) Complementary angles

(b) Vertical angles

(c) Supplementary angles

<u>Explanation:</u>

Complementary angles are those two angles whose sum is 90 degrees.

Supplementary angles are those two angles whose sum is 180 degrees.

Vertical angles are the angles opposite each other when two lines cross.

(a)

Angles 1 and 5 are complementary angles

(b)

Angles 3 and 5 are vertical angles

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3 years ago
Given the information in the diagram below, find the measure of angle N. Use RACE and complete sentences to show how you found t
Sonja [21]

Answer:

m<N = 76°

Step-by-step explanation:

Given:

∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).

m<J = 64° (given)

Required:

m<N

SOLUTION:

m<K = m<J (base angles of an isosceles ∆ are equal)

m<K = 64° (Substitution)

m<K + m<J + m<JLK = 180° (sum of ∆)

64° + 64° + m<JLK = 180° (substitution)

128° + m<JLK = 180°

subtract 128 from each side

m<JLK = 180° - 128°

m<JLK = 52°

In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.

Thus:

m<MLN = m<JKL (vertical angles are congruent)

m<MLN = 52°

m<M = m<MLN (base angles of isosceles ∆MNL)

m<M = 52° (substitution)

m<N + m<M° + m<MLN = 180° (Sum of ∆)

m<N + 52° + 52° = 180° (Substitution)

m<N + 104° = 180°

subtract 104 from each side

m<N = 180° - 104°

m<N = 76°

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2 years ago
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The equation in slope intercept form is:

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Our equation is then y=-3x-b

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3 years ago
Put the following equation of a line into slope-intercept form, simplifying all
dmitriy555 [2]

Answer:

Brainliest!

Step-by-step explanation:

slope intercept form is in: y = mx + b

12y = -8x + 48

y = (-8x+48)/12

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Lb = 64 oz Helppppppppppppp me<br><img src="https://tex.z-dn.net/?f=5" id="TexFormula1" title="5" alt="5" align="absmiddle" clas
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