Find the equation of the line. Use exact numbers.

At the first pep rally of the season, the football team and the volleyball team were presented to the student body. During the p

Darina [25.2K]

Answer:

A. f + y ≤ 11

17f + 287 ≤ 242

Step-by-step explanation:

[] Let f be football players and v be volleyball players.

-> The total time must be less than or equal to 242 seconds.

-> If football players talked for 17 seconds, we can write it as 17f.

-> If volleyball players talked for 28 seconds, we can write it as 28v.

[] Coming back to the first point I made, the total time must be less than or equal to 242 seconds.

-> 17f + 28v ≤ 242

[] This is going to be a part of our system of inequalities

-> Because of this, we rule out the following options.

B & D - the football players talk for 17 seconds, not the volleyball players

C - not less than or equal too, only less than

[] This leaves us with the option of A.

-> The first part of it also works. If 11 players can talk to the crowd, then the total of f and v must be equal too or less than 11.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

5 0

3 years ago

Let

Digiron [165]

What I gather from the question is that $X$ has second moment $E(X^2)=81$ and variance $V(X) = 58$ , and you're asked to find the expectation and variance of the random variable $Y=2X+10$ .

From the given second moment and variance, we find the expectation of $X$ :

$V(X) = E(X^2) - E(X)^2 \implies E(X) = \sqrt{E(X^2) - V(X)} = \sqrt{23}$

Expectation is linear, so

$E(Y) = E(2X+10) = 2 E(X) + 10 = \boxed{2\sqrt{23} + 10}$

Using the same variance identity, we have

$V(Y) = V(2X+10) = E((2X+10)^2) - E(2X+10)^2$

and

$E((2X+10)^2) = E(4X^2 + 40X + 100) = 4E(X^2) + 40E(X) + 100 = 424 + 40\sqrt{23}$

so that

$V(Y) = V(2X+10) = (424 + 40\sqrt{23}) - (2\sqrt{23} + 10)^2 = \boxed{232}$

Alternatively, we can use the identity

$V(aX+b) = a^2 V(X) \implies V(2X+10) = 4V(X) = 232$

5 0

2 years ago

A company manufactures two products. A and B on two machines, I and II. It has been determined that the company will realize a p

Andrews [41]

Answer:

product A on machine 1 would make 27 units (rounded down) 81 dollars profit.

product A on machine 2 would make 25 units (rounded down) 75 dollars profit.

product b on machine 1 would make 15 units (rounded down) 75 dollars profit.

product b on machine 2 would make 16 units (rounded down) 80 dollars profit.

Step-by-step explanation:

a1 refers to product a on machine 1

a2 refers to product a on machine 2

same rule applies for product b 1 and 2

4 0

4 years ago

Please answer this! Will award Brainliest!

serg [7]

Answer:

2^20/3^8

Step-by-step explanation:

6 0

4 years ago

Count by ones from 368 to 500. Change for a larger unit when necessary.

stepan [7]

We can figure out how many numbers there are from 368 to 500 by subtracting.

500 - 368 = 132

Now, we need to get it in word form. This can be done by looking at the place value of each number.. So your answer would be:

1 hundred, 3 tens, and 2 ones.

6 0

4 years ago