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harina [27]
3 years ago
14

At the museum, the O'Rourke family bought 3 adult tickets and 2 children tickets for $23.50. The Patel family bought 2 adult tic

kets and 4 children's tickets for $25. Find the cost of each type of ticket.
Mathematics
1 answer:
Tresset [83]3 years ago
4 0
6.25 for each kids ticket and 11.75 for each adult ticket
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1/3

Step-by-step explanation:

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the four sections would be 60 x 60 since 900 is 30 x 30

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Answer:

h = 5t

Step-by-step explanation:

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1 year ago
Trade associations, such as the United Dairy Farmers Association, frequently conduct surveys to identify characteristics of thei
asambeis [7]

Complete Question

Trade associations, such as the United Dairy Farmers Association, frequently conduct surveys to identify characteristics of their membership. If this organization conducted a survey to estimate the annual per-capital consumption of milk and wanted to be 95% confident that the estimate was no more than 0.5 gallon away from the actual average, what sample size is needed? Past data have indicated that the standard deviation of consumption of approximately 10 gallons.

Answer:

The  sample size is  n  = 1537 \ gallons

Step-by-step explanation:

From the question we are told that

    The margin of error is  MOE  = 0.5

     The confidence level is  C  =  95%

Given that the confidence level is  95% the level of significance is mathematically represented as

         \alpha  =  100 -  95

         \alpha  =  5%

         \alpha  = 0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table , the values is  Z_{\frac{\alpha }{2} } = 1. 96

The reason we are obtaining critical values of  

\frac{\alpha }{2}

instead of  

\alpha

is because  

\alpha

represents the area under the normal curve where the confidence level interval (

1-\alpha

) did not cover which include both the left and right tail while  

\frac{\alpha }{2}

is just the area of one tail which what we required to calculate the sample size

Now the sample size is mathematically represented as

          n  =  \frac{[Z_{\frac{\alpha }{2} }] ^2 *  \sigma ^2}{MOE^2}

substituting values

         n  =  \frac{1.96^2 * 10 ^2}{0.5^2}

         n  = 1537 \ gallons

7 0
3 years ago
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