The tickets aren't replaced, so multiply the probabilities, decreasing the denominator each time.
a) 1/48
b) (1/48)(1/47)
c) (1/48)(1/47)(1/46)(1/45)(1/44)(1/43)
It will just be 2 since 10 goes into 20 2 times
Define
g = 9.8 32.2 ft/s², the acceleration due to gravity.
Refer to the diagram shown below.
The initial height at 123 feet above ground is the reference position. Therefore the ground is at a height of - 123 ft, measured upward.
Because the initial upward velocity is - 11 ft/s, the height at time t seconds is
h(t) = -11t - (1/2)gt²
or
h(t) = -11t - 16.1t²
When the ball hits the ground, h = -123.
Therefore
-11t - 16.1t² = -123
11t + 16.1t² = 123
16.1t² + 11t - 123 = 0
t² + 0.6832t - 7.64 = 0
Solve with the quadratic formula.
t = (1/2) [-0.6832 +/- √(0.4668 + 30.56) ] = 2.4435 or -3.1267 s
Reject the negative answer.
The ball strikes the ground after 2.44 seconds.
Answer: 2.44 s
Answer:
h(0) = –16t^2 + 32t + 48
Step-by-step explanation:
If everything with a t is multiplied by zero, it will make everything 0 and leave the value of the constant, 48.
Answer:
A) 4 units right, 4 units down.
Step-by-step explanation:
By counting, it can be discovered that the figure is translated in this way.
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