Answer:
10 and 42
Step-by-step explanation:
The difficulty with word problems is translating them into math.
Let's do that
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The sum of a number and two times a smaller number is 62.
let's call the bigger number b, and the smaller number s
b + 2s = 62
Three times the bigger number exceeds the smaller number by 116
3b = s + 116
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Now manipulate one of the equations to isolate the variable
3b = s + 116
Subtract 116 from both sides
3b - 116 = s
substitute for s = 3b - 116 in
b + 2s = 62
b + 2(3b - 116) = 62
Distribute
b + 6b - 232 = 62
combine like terms
7b = 294
Divide both sides by 7
b = 42
to find s plug in b = 42 into
b + 2s = 62
42 + 2s = 62
subtract 42 from both side
2s = 20
divide both sides by 2
s = 10
