AutoSum is a feature in Microsoft Excel which involves you as the user being able to input some sort of formula and for it to apply to all selected cells. It works in many different ways. For example, it has the ability to auto fill so that it fills the cells with numbers from 1-100. Or days of the week, or months of the year. If you were creating a Gantt chart for project management, you would want to auto fill the consecutive days of which you want the project to run for.
True because any one can change or fix their voice just by practicing a voice.
The answer is either B) or D) because I remember learning this and the keyword I remember is analogue
Hope this helps —- XoXo
Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
int A[3][3],B[3][3],res[3][3],i,j;
srand(time(0));//for seed.
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
int val=rand()%100+1;//generating random values in range 1 to 100.
int val2=rand()%100+1;
A[i][j]=val;
B[i][j]=val2;
}
cout<<endl;
}
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
res[i][j]=0.5*A[i][j]+3*B[i][j];//storing the result in matrix res.
}
}
cout<<"Matrix A is"<<endl;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
cout<<A[i][j]<<" ";//printing matrix A..
}
cout<<endl;
}
cout<<"Matrix B is"<<endl;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
cout<<B[i][j]<<" ";//printing matrix B..
}
cout<<endl;
}
cout<<"The result is"<<endl;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
cout<<res[i][j]<<" ";//printing the result..
}
cout<<endl;
}
return 0;
}
Output:-
Matrix A is
13 95 83
88 7 14
24 22 100
Matrix B is
11 13 95
48 35 20
68 100 18
The result is
39.5 86.5 326.5
188 108.5 67
216 311 104
Explanation:
I have created 2 matrices A and B and storing random numbers int the matrices A and B.Then after that storing the result in res matrix of type double to store decimal values also.Then printing the res matrix.
Global knowledge is like common sense, people know these things, but their may be someone else with the same idea. One person can come up with the idea but their is also another with same so don't give someone to much credit.
