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Tresset [83]
3 years ago
15

In this lab you will learn about the concept of Normal Forms for refining your database design. You will then apply the normaliz

ation rules: 1NF, 2NF and 3NF to enhance your database design. Lab Steps: Read about the Normal Forms in your textbook, chapter 14, pages 474 to 483. Check the learning materials on Normal Forms under the Learning Materials folder of Week 5. Apply the Normalization rules to your database design. Describe in words how 1NF, 2NF and 3NF apply to your design/database schema. Apply all the modifications that you made due to applying NF rules to your actual database in the DBMS (MS SQL Server). Put your explanation for how 1NF, 2NF and 3NF apply to your database in a Word document OR PowerPoint presentation.
Computers and Technology
1 answer:
noname [10]3 years ago
7 0

Answer:

I don't know

Explanation:

is about knowing how to make use of the refinery

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Suppose that the content of the input file is: 14 13 26 8 -11 36 0 -1. What is the output of the following code? ifstream myInfi
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Which branch of science helps avoid or minimize stress-related injuries at workplace
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Critical Thinking Questions
Hoochie [10]

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One example of syntax in Logo is “[”. Two examples of Java are “;” and “{“or “}”. If you don’t use these parts of syntax then you could get a Syntax error, this will make you have to stop the code and debug.

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2 years ago
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Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs
marishachu [46]

Answer:

  1.    public static String bothStart(String text1, String text2){
  2.        String s = "";
  3.        if(text1.length() > text2.length()) {
  4.            for (int i = 0; i < text2.length(); i++) {
  5.                if (text1.charAt(i) == text2.charAt(i)) {
  6.                    s += text1.charAt(i);
  7.                }else{
  8.                    break;
  9.                }
  10.            }
  11.            return s;
  12.        }else{
  13.            for (int i = 0; i < text1.length(); i++) {
  14.                if (text1.charAt(i) == text2.charAt(i)) {
  15.                    s += text1.charAt(i);
  16.                }else{
  17.                    break;
  18.                }
  19.            }
  20.            return s;
  21.        }
  22.    }

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0
3 years ago
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