True or false : y = 2x+2 is the same as 2x+2 = y ?
1 answer:
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<u>Given</u>:
Given that two lines are intersecting at the point.
The angles (3x - 8)° and (2x + 12)° are the angles formed by the intersection of the two lines.
We need to determine the equation to solve for x and the value of x.
<u>Equation:</u>
The two angles (3x - 8)° and (2x + 12)° are vertically opposite. Hence, the vertically opposite angles are always equal.
Hence, we have;
Hence, the equation is
<u>Value of x:</u>
The value of x can be determined by solving the equation
Thus, we have;
Subtracting both sides of the equation by 2x, we get;
Adding both sides of the equation by 8, we get;
Thus, the value of x is 20.
Hence, the equation and the value of x are
Thus, Option D is the correct answer.
Check the picture below
now, we know is a parallelogram, so the diagonals will bisect
looking at the picture, the interior angles are not right-angles, and thus is not a rectangle, and is not a square either, due to the same reason
is it a rhombus? well, a rhombus, is a parallelogram, that's "slanted" per se, but regardless of how slanted it may be, the sides are all equal
now, we don't need to check the length of both pairs, just one of the segments of each pair, let's check only then JK and KL, the ones in red in the picture, since each pair of segments are twin, if JK = KL, then that means all sides are equal
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) J&({{-7 }}\quad ,&{{ -2}})\quad % (c,d) K&({{ 0}}\quad ,&{{ 4}})\\\\ K&({{ 0}}\quad ,&{{ 4}})\quad % (c,d) L&({{ 9}}\quad ,&{{ 2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ JK=\sqrt{[0-(-7)]^2+[4-(-2)]^2}\implies JK=\sqrt{(0+7)^2+(4+2)^2} \\\\\\ JK=\sqrt{7^2+6^2} \\\\\\ KL=\sqrt{(9-0)^2+(2-4)^2}\implies KL=\sqrt{9^2+(-2)^2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AJ%26%28%7B%7B-7%20%7D%7D%5Cquad%20%2C%26%7B%7B%20-2%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AK%26%28%7B%7B%200%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5C%5C%5C%5C%0AK%26%28%7B%7B%200%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AL%26%28%7B%7B%209%7D%7D%5Cquad%20%2C%26%7B%7B%202%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AJK%3D%5Csqrt%7B%5B0-%28-7%29%5D%5E2%2B%5B4-%28-2%29%5D%5E2%7D%5Cimplies%20JK%3D%5Csqrt%7B%280%2B7%29%5E2%2B%284%2B2%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AJK%3D%5Csqrt%7B7%5E2%2B6%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AKL%3D%5Csqrt%7B%289-0%29%5E2%2B%282-4%29%5E2%7D%5Cimplies%20KL%3D%5Csqrt%7B9%5E2%2B%28-2%29%5E2%7D)
now... another characteristic of a rhombus is, the diagonals, meet at right-angle, that means KM ⟂ JL
and that simply means, if you get the slope of KM and the slope of JL, the product of their slope is -1
then multiply both slopes, if their product is -1, that means, they're perpendicular to each other, and it IS a rhombus only, then.
now, we know is a parallelogram, so the diagonals will bisect
looking at the picture, the interior angles are not right-angles, and thus is not a rectangle, and is not a square either, due to the same reason
is it a rhombus? well, a rhombus, is a parallelogram, that's "slanted" per se, but regardless of how slanted it may be, the sides are all equal
now, we don't need to check the length of both pairs, just one of the segments of each pair, let's check only then JK and KL, the ones in red in the picture, since each pair of segments are twin, if JK = KL, then that means all sides are equal
now... another characteristic of a rhombus is, the diagonals, meet at right-angle, that means KM ⟂ JL
and that simply means, if you get the slope of KM and the slope of JL, the product of their slope is -1
then multiply both slopes, if their product is -1, that means, they're perpendicular to each other, and it IS a rhombus only, then.