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loris [4]
3 years ago
11

What is 3/6 plus 1/3

Mathematics
2 answers:
aksik [14]3 years ago
6 0

Answer:

5/6

Step-by-step explanation:

3/6 + 1/3 = 3/6 + 2/6 = 5/6

alekssr [168]3 years ago
5 0

Answer:

5/6

Step-by-step explanation:

3/6 + 1/3 = 3/6 + 2/6 = 5/6

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Bridget, June and Colin share £88 in a ratio 3:3:2. How much money does each person get?
astra-53 [7]

Answer

33,33 and 22

Step-by-step explanation:

4 0
2 years ago
What is the equation?
pishuonlain [190]

Answer:

(x - 7)^2 + (y - 2)^2 = 5^2

Step-by-step explanation:

Center at (7, 2); radius 5

Adapt (x - h)^2 + (y - k)^2 = r^2 to this situation.  Replace h by 7, k by 2 and r by 5:

(x - 7)^2 + (y - 2)^2 = 5^2

3 0
3 years ago
How do you solve equations that contain addition or subtraction
ollegr [7]
To solve an addition problem, you simply add one number to the other. For example, If I want to add 4 to 5, I would write the equation 4 + 5 = 9. To solve a subtraction problem, you simply take a number away from another. For example, If I want to take 5 away from 9, I would write the equation 9 - 5 = 4. Hope I helped! :)
7 0
3 years ago
Jason started with 12 1/2 pounds of concrete to set fence post. He used 4 1/6 pounds for the center post abd 3 1/3 pounds for th
Kruka [31]
He has 5 pounds left
7 0
3 years ago
A company offers you a job with an annual salary of $70 000 for the first year and a 5% raise every year after. Approximately ho
mariarad [96]

Answer:

$386794

Step-by-step explanation:

To be able to find how much we get in 5 years, we need to base it off the initial salary value.

So in the first year we get.

$70,000

To get how much we get in the 2nd year we add the extra 5%.

2nd year salary = (1.05)70000

2nd year salary = 73500

Now we continue to do that until the 5th year

3rd year = (1.05)73500

3rd year = 77175

4th year = (1.05) + 77175

4th year = 81033.75

5th year = (1.05) + 81033.75

5th year = 85085.44

Now we add them all up to get the total.

70000 + 73500 + 77175 + 81033.75 + 85085.44 = $386794.19 or $386794

7 0
3 years ago
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