<span>300000000 is the answer to this question</span>
No solution as they are parallel lines. so, inconsistent
Answer: 1.48ft
Step-by-step explanation:
The angle, θ, at which the projector "spreads" the image is constant.
We know that:
"A movie projector positioned 34 feet from a wall creates an image that is 8 feet wide on the wall"
We can think this problem as the image in the end, two triangle rectangles with cathetus equal to 34 ft, and 8/2 ft = 4ft
Then this angle θ can be calculated because we know the two cathetus of this triangle:
Tan(θ) = (opposite cathetus)/(adjacent cathetus)
Tan(θ) = 4ft/34ft
θ = Cotan(4/34) = 8.46°
Now, if you move the place the projector 5ft from the wall, now the adjacent cathetus is 5ft instead of 34.
Then we have:
Tan(8.46°) = x/5ft
Tan(8.46°)*5ft = x = 0.74ft
But remember that the actual width of the image will be two times that, so the width is:
W = 2*0.74ft = 1.48ft
Answer:
x = 42 degrees
y = 37 degrees
Step-by-step explanation:
Those are right angle triangles. So you know the right angles are 90 degrees, and each triangle gives you the measurement of another angle.
So, take the triangle in the top left (x):
180 - 90 - 48 = x
Same with the other triangle (y)
180 - 90 - 53 = y
Two thirds times four equals eight thirds or two and two thirds cups