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guajiro [1.7K]
3 years ago
11

How about this one −p+

Mathematics
1 answer:
Bond [772]3 years ago
5 0

Answer:

NaNx10^-23

Step-by-step explanation:

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Every week, Mr. Kirkson uses 3 1/6 gallon of water to water every 1/3 square foot of his garden. How many gallons of water does
nata0808 [166]

3 1/6 / 1/3 =

19/6 / 1/3 =

19/6 * 3/1 = 57/6 = 9 1/2 gallons per square foot

5 0
2 years ago
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Please help me?? Solve for x
Delvig [45]
X= 10

This is because 180-95= 85 which would make 8x+5= 85

Subtract 5 from both sides and get 8x=80

Then, divide 8 from both sides and get x=10
3 0
2 years ago
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The annual energy consumption of the town where Camilla lives in creases at a rate that is onal at any time to the energy consum
boyakko [2]

Answer:

6.575 trillion BTUs

Step-by-step explanation:

<em>Let represent the annual energy consumption of the town as E</em>

<em>The rate of annual energy consumption *  energy consumption at time past</em>

<em>dE/dt * E</em>

<em>dE/dt =K</em>

<em>k = the proportionality constant</em>

<em>c= the integration constant</em>

<em>(dE/dt=) kdt</em>

<em>lnE = kt + c</em>

<em>E(t) = e^kt+c ⇒ e^c e^kt  e^c is a constant, and e^c = E₀</em>

<em>E(t) = E₀ e^kt</em>

<em>The initial consumption of energy is E(0)=4.4TBTU</em>

<em>set t = 0 then</em>

<em>4.4 = E₀ e⇒ E₀ (1) </em>

<em>E₀ = 4.4</em>

<em>E (t) = 4.4e^kt</em>

<em>The consumption after 5 years is t = 5, e(5) = 5.5TBTU</em>

<em>so,</em>

<em>E(5) = 5.5 = 4.4e^k(5)</em>

<em>e^5k = 5/4</em>

<em>We now take the log 5kln = ln(5/4)</em>

<em>5k(1) = ln(5/4)</em>

<em>k = 1/5 ln(5/4) = 0.04463</em>

<em>We find  the town's annual energy consumption, after 9 years</em>

<em>we set t=9  </em>

<em>E(9) = 4.4e^0.04463(9)</em>

<em>= 4.4(1.494301) = 6.5749TBTUs</em>

<em>Therefore the annual energy consumption of the town after 9 years is </em>

<em>= 6.575 trillion BTUs</em>

<em />

3 0
3 years ago
During the day, the temperature in Nome, Alaska rose 35°. The low temperature for the day was −22°F. What was the high temperatu
Marysya12 [62]

For this one add 35 to the -22 degrees.  So the equation is 35+(-22) which would equal 13 degrees F for a high.

5 0
2 years ago
A 35% sodium hydroxide solution is to be mixed with a 60% sodium hydroxide solution to obtain 20 liters of 40% sodium hydroxide
nydimaria [60]
0.35x + 0.60y = 0.40(x + y)   where x = vol. of 35% and y = vol. of 60%

x + y = 20

solve this system of equations

x  +  y =  20
-0.05x +0.20y = 0

this gives x = 16 and y = 4

so you need 16 L of 35% and 4 L of 60% solution.


3 0
3 years ago
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