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guajiro [1.7K]
3 years ago
11

How about this one −p+

Mathematics
1 answer:
Bond [772]3 years ago
5 0

Answer:

NaNx10^-23

Step-by-step explanation:

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An analysis of the decay of 10 grams of an unstable element over time was completed and is displayed in the computer output.
Lady bird [3.3K]

The equation of the least-squared regression line is: In(Element) = 2.305 - 0.101(Time).

<h3>What is a regression line?</h3>

A regression line displays the connection between scattered data points in any set. It shows the relation between the dependent y variable and independent x variables when there is a linear pattern.

According to the given problem,

From the table we can see,

ln(Element) is the dependent variable and Time is the independent variable.

The constant = 2.305,

Time = -0.101

Hence, we can conclude, our least squared regression line will be

In (Element) = 2.305 - 0.101 (Time).

Learn more about regression line here: brainly.com/question/7656407

#SPJ2

6 0
2 years ago
Craig just purchased a new car. He financed $45000 and must pay it back over 5 years with 11% interest. a) How much will craig h
nignag [31]

Answer:

49950

Step-by-step explanation:

111% of 45000 is 49950

5 0
3 years ago
Read 2 more answers
Choose the point-slope form of the equation below that represents the line that passes through the point (−1, 6) and has a slope
IrinaVladis [17]

Answer:

The correct answer is option B.

Step-by-step explanation:

Two point form of the equation:

(y-y_1)=\frac{y_2-y_1}{x_2-x_1}\times (x-x_1)

\frac{y_2-y_1}{x_2-x_1}=Slope=m

(y-y_1)=m\times (x-x_1)

A line passing through the point (-1,6) with slope ,m = -3.

The equation of the line will be:

y-6=(-3)(x-(-1))=(-3)(x+1)

Hence, the correct answer is option B.

3 0
3 years ago
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Jake won 7 of the 15 races he ran. Write Jake's fraction of decimal. wins as a
denis-greek [22]

Answer:

0.46

Step-by-step explanation:

7 0
3 years ago
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Ms. Friedman and Mrs. Elliot both teach
sertanlavr [38]
Answer- Total area of both rooms and the storage =2844ft^2
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3 years ago
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