Please help!! Select the values for the domain & range of the function given below.

Mathematics

1 answer:

VladimirAG [237]3 years ago

4 0

Answer:

the first one n second one

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Find the distance and midpoint for the following coordinates.<br> P(7.6 , 10.1) and Q(4.6 , 3.1)

KATRIN_1 [288]

Solving for the midpoint:

x - coordinate: (7.6 + 4.6)/2 = 6.1
y - coordinate: (10.1 + 3.1)/2 = 6.6

Midpoint: (6.1 , 6.6)

Solving for the distance:

Distance formula: sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

D = sqrt( (7.6 - 4.6)^2 + (10.1 - 3.1)^2 <span>)
D = sqrt( 3^2 + 7^2)
D = sqrt(58)
D = 7.62 units

Distance = 7.62 units</span>

8 0

3 years ago

Is .0035 infinite or finite

marishachu [46]

0.0032 is finite because it doesn't go on forever. If that number never ended, it would be infinite. I hope this helps!

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3 years ago

Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side

svp [43]

A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6

Last, we have all the information needed in order to calculate the area by the formula:

$A = \frac{(AB + CD)DH}{2}$

A = (7 + 5) × 2√6 ÷ 2
= 12√6

The area of the regular trapezoid is 12√6 square units.