Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
Answer:
C
Step-by-step explanation:
To find the value of the function at x = - 2
Locate x = - 2 on the x- axis then go up vertically until the line is met.
The read the corresponding value of y from the y- axis
x = - 2 ⇒ y = 2 → C
Answer:
B. 66
Step-by-step explanation:
45% of 400
.45 x 400 = 180 (number of girls)
400 - 180 = 220 (number of boys)
30% of 220
.30 x 220 = 66
Answer:
3/14
Step-by-step explanation:
P=3/(3+4+7)=3/14 because each of 14 marbles is equally likely to be drawn.
Hope this helped :)
Have a great day!