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IRINA_888 [86]
3 years ago
15

Find the missing term in the proportion: 1/y = 4/11 y=?

Mathematics
2 answers:
photoshop1234 [79]3 years ago
5 0

Answer:

2.75, or 2 3/4

Step-by-step explanation:

Cross multiply first to get:

4y = 11

Divide by 4 on both sides

y = 2.75

Now, simplify to a mixed number or keep it as a decimal to get 2.75, or 2 3/4.

Hope this helps!

If there is something wrong, just let me know.

ivann1987 [24]3 years ago
5 0

Answer:

2.75

Step-by-step explanation:

1/y = 4/11 cross multiply the expressions

4y = 11 divide both sides by 4

y = 2.75

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What is the difference between an inequality and an equation?​
pshichka [43]

Hello there here is your answer!

An equation is a expression that contains an equals sign. (=) An inequality is a expression that contains inequality signs ().

Hope this helps! If so, mark me brainliest please!

5 0
3 years ago
See picture for problem. Please answer if you know
skelet666 [1.2K]

Answer: rx-sx= -2x^2

rx+sx=4x^2+8x

(r)(s)=3x^2+16x+16

Step-by-step explanation: Hopefully this helps! :)

4 0
3 years ago
Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.
dedylja [7]

y =  \frac{ - 1}{4} x +  \frac{1}{2}

4 0
2 years ago
A 4 digit number starts23. The next two digits are 3 times the first 2 digits. Multiply this 4 digit number by 678 . What is prd
kari74 [83]

Answer:

1,606,182

Step-by-step explanation:

23_ _

23 times 3 = 69

2369

2369 times 678

= 1,606,182

3 0
3 years ago
P(x)= x^5-4x^4+3x^3+2x-6 <br> Use Descartes rule of signs to analyze the zeros
maxonik [38]
\bf \begin{array}{cccccccccccllll}&#10;P(x)= x^5&-&4x^4&+&3x^3&+&2x&-&6\\&#10;&yes&&yes&&\textit{no}&&yes&#10;\\\\\\&#10;P(-x)= -x^5&-&4x^4&-&3x^3&-&2x&-&6\\&#10;&\textit{no}&&\textit{no}&&\textit{no}&&\textit{no}&#10;\end{array}

notice where how many "yes" sign change happen in the positive "x"
and the on the negative "-x"

for the P(x) is 3 changes, thus
so is either 3 real positive ones, or 3-2 = 1 real positive one

P(-x) gives no sign changes, so there are 0 negative ones

the polynomial has a degree of 5, thus 5 roots
if it has 3 real positive ones, then it has 2 complex ones
the complex ones pick up the slack per se

if it has 1 real positive one, then it has 4 complex ones

bear in mind complex ones always come in pairs


8 0
3 years ago
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