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Grace [21]
3 years ago
14

Are 2/3 and 2/6 the same?

Mathematics
2 answers:
ANTONII [103]3 years ago
6 0
No they aren't. 2/3 is greater than 2/6
xz_007 [3.2K]3 years ago
5 0

Answer:

No they are not this is because 2/3 is greater than 2/6

Step-by-step explanation:

hope this helps! have a wonderful day!

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Please Help!<br> Factor the following trinomial<br> <img src="https://tex.z-dn.net/?f=9x%5E2-24x%2B16" id="TexFormula1" title="9
AlexFokin [52]

\huge\colorbox{pink}{Hey \: panda!}

The answer=>

For this,we need to know what's Middle splitting method

  • In order to factorize x² + bx + c we have to find numbers p and q such that p + q = b and pq = c. After finding p and q, we split the middle term in the quadratic as <em><u>px + qx and</u></em> get desired factors by grouping the terms.

Step-by-step explanation:

9x {}^{2}  - 24x + 16 \\  =  > 9x {}^{2}  - 12x - 12x + 16 \\  =  > 3x(3x - 4) - 4(3x - 4) \\  =  > (3x - 4)(3x - 4) \\ so... \\ x = eitherway \: 4

i.e

Alpha= Beta = 4

5 0
3 years ago
Read 2 more answers
Amy is scuba diving. She starts at – 15.5 m relative to the ocean surface. She swims
solniwko [45]

Answer:

-9.85

Step-by-step explanation:

-15.5 - 4.2 = -19.7

Negatives work like positives

19.7 / 2 = 9.85

Turn that into a negative

-9.85

3 0
2 years ago
There is a triangle with a perimeter of 63 cm, one side of which is 21 cm. Also, one of the medians is perpendicular to one of t
NemiM [27]

Answer:

21cm; 28cm; 14cm

Step-by-step explanation:

There is no info in the problem/s  text which one of the triangle's  side is 21 cm. That is why we have to try all possible variants.

Let the triangle is ABC . Let the AK is the angle A bisector and BM is median.

Let O is AK and BM cross point.

Have a look to triangle ABM.  AO is the bisector and AOB=AOM=90 degrees (means that AO is as bisector as altitude)

=> triangle ABM is isosceles => AB=AM  (1)

1. Let AC=21   So AM=21/2=10.5 cm

So AB=10.5 cm as well.  So BC= P-AB-AC=63-21-10.5=31.5 cm

Such triangle doesn' t exist ( is impossible), because the triangle's inequality doesn't fulfill.  AB+AC>BC ( We have 21+10.5=31.5 => AB+AC=BC)

2. Let AB=21 So AM=21 and AC=42 .So  BC= P-AB-AC=63-21-42=0 cm- such triangle doesn't exist.

3. Finally let BC=21 cm. So AB+AC= 63-21=42 cm

We know (1) that AB=AM so AC=2*AB.  So AB+AC=AB+2*AB=3*AB

=>3*AB=42=> AB=14 cm => AC=2*14=28 cm.

Let check if this triangle exists ( if the triangle's inequality fulfills).

BC+AB>AC    21+14>28 - correct=> the triangle with the sides' length 21cm,14 cm, 28cm exists.

This variant is the only possible solution of the given problem.

6 0
3 years ago
Help me plz I’m struggling with this
swat32

Answer:

if you zoom in a little bit and repost it i can help you

Step-by-step explanation:

5 0
3 years ago
Mr. Crosby's is driving jack, cassidy, and victor to the library. Jake lives 1/4 miles from the library, cassidy lives 1)3 mile
irakobra [83]

Answer:

5/8, 1/3, 1/4

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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