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Grace [21]
3 years ago
14

Are 2/3 and 2/6 the same?

Mathematics
2 answers:
ANTONII [103]3 years ago
6 0
No they aren't. 2/3 is greater than 2/6
xz_007 [3.2K]3 years ago
5 0

Answer:

No they are not this is because 2/3 is greater than 2/6

Step-by-step explanation:

hope this helps! have a wonderful day!

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Jorge bikes to school each day. If he can travel 33 miles in 11 hours, how fast does he travel in one
Eddi Din [679]

33 miles divided by 11 hours will give you the mile per hour traveled.

Answer: 3 miles per hr

3 0
3 years ago
95-a(b+c) when a= 9, b = 3 and c=7.4 I don’t get how to solve this please put an explanation
Marianna [84]

Notice that in the statement of the exercise are the values of a, b and c. Then, to evaluate the given expression, we replace the given values of a, b, and c. So, we have:

\begin{gathered} a=9 \\ b=3 \\ c=7.4 \\ 95-a\mleft(b+c\mright) \\ \text{ We replace the given values} \\ 95-a(b+c)=95-9(3+7.4) \\ 95-a(b+c)=95-9(10.4) \\ 95-a(b+c)=95-93.6 \\ 95-a(b+c)=\boldsymbol{1.4} \end{gathered}

Therefore, the result of evaluating the given expression when a = 9, b = 3, and c = 7.4 is 1.4.

7 0
1 year ago
Through (-20,4) and <br> perpendicular to y=x+5
WITCHER [35]
<h3>Answer:  y = -x - 16</h3>

========================================================

Explanation:

The given equation is the same as y = 1x+5 which is in y = mx+b form.

  • m = slope = 1
  • b = y intercept = 5

Anything perpendicular to this will have a slope of -1, which is the negative reciprocal of the original slope.

We'll use this perpendicular slope along with (x,y) = (-20,4) to find the equation of the perpendicular line.

y = mx+b

y = -1x+b ... plug in the perpendicular slope

4 = -1*(-20)+b ... plug in the x,y coordinates

4 = 20+b

4-20 = b

-16 = b

b = -16

Therefore, we go from y = mx+b to y = -x-16

4 0
3 years ago
What is the solution to the equation: 7p-3(p+1)=-2p+33
andreyandreev [35.5K]

Answer:

Step-by-step explanation:

7p - 3p - 3 = -2p + 33

4p - 3 = -2p + 33

6p - 3 = 33

6p = 36

p = 6

8 0
3 years ago
Questions 1 &amp; 2??????????
Alja [10]
<span>1) C. Paul and Sarah 2) D. I, III and IV For the first problem, let's look at the three proposed transformations and see which one(s) work. Mark. The points were reflected across the line y = x. Point A (-6,8) would translate to (8,-6) which is not correct. So Mark's idea is wrong. Paul, Reflect over the X-axis, then the Y-axis. Point A(-6,8) => (-6,-8) => (6,-8) Correct Point B(-2,2) => (-2,-2) => (2,-2) Correct Point C(-8,5) => (-8,-5) => (8,-5) Correct So Paul's translation works. Sarah, Rotate 180 degrees around (0,0) Point A(-6,8) => (6,-8) Correct Point B(-2,2) => (2,-2) Correct Point C(-8,5) => (8,-5) Correct So Sarah's translation works. So both Paul and Sarah have a translation that works.Looking at the available choices, the correct answer is C. Paul and Sarah The triangle OCD is given as congruent to the triangle JAL. That means that all the angles and lengths for each triangle matches the angle and length in the other triangle. Basically, both triangles are identical to each other. So let's see about the choices. I. is line segment OC congruent to line segment JA? Yes. OC is the first segment in the triangle OCD and JA is the first segment in triangle JAL. So they're congruent by definition. II. Is line segment OD congruent to line segment AL? No. Segment OD would be congruent to segment JL, or segment CD would be congruent to segment AL. III. Is angle COD congruent to angle AJL? Yes. COD is the angle around point O which is the 1st point in triangle OCD and AJL is the angle around point J which is also the 1st point in the triangle JAL. So they're congruent by definition. IV. Is the angle DCO congruent to angle JAL? C is the second point in triangle OCD and A is the second point in triangle JAL. The measure of the angle doesn't matter which way you're going. So they're congruent as well. So I, III, and IV are all true with II being false. Looking at the available choices, you see that "D. I, III and IV" is the correct answer.</span>
5 0
3 years ago
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