<h2>
Question:</h2>
Find k if (x+1) is a factor of 2x³ + kx² + 1
<h2>
Answer:</h2>
k = 1
<h2>
Step-by-step explanation:</h2>
The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.
<em>This is because;</em>
i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.
ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e
=> (-3)² - 9
=> (9) - 9 = 0
Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.
<em><u>From the question</u></em>
Given polynomial: 2x³ + kx² + 1
Given factor: x + 1.
Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e
2(-1)³ + k(-1)² + 1 = 0
2(-1) + k(1) + 1 = 0
-2 + k + 1 = 0
k - 1 = 0
k = 1
Therefore the value of k is 1.
Answer:
160 miles
Step-by-step explanation:
Company A form $130 a day plus $0.30 per mile
Company A = 130 + 0.30x
Company B charges $50 a day plus $0.80 per mile
Company B = 50 + 0.80x
Where,
x = number of miles
Equate the cost of company A and company B
130 + 0.30x = 50 + 0.80x
Collect like terms
130 - 50 = 0.80x - 0.30x
80 = 0.50x
Divide both sides by 0.50x
x = 80 / 0.50
= 160
x = 160 miles
The number of miles in a day at which the rental costs for Company A and Company B are the same is 160 miles
Using the quadratic equation we get:
Factoring out 2 we get
Factoring out the imaginary number:
So b.
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