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3 years ago

Brand W: 500 napkins for $2.87

1 answer:

3 0

The best way, in my opinion, to do this, is to find the unit rate of each napkin brand, or the cost per napkin. To do this, divide the money amount by the amount of napkin they give you.

/Brand W:2.87/500=.00574 \
\Brand X: 1.27/200=.00635   \ These are the
/Brand Y: .62/100 =.0062   / cost per napkin.
  \Brand Z: 1.37/250=.00548 /

Which one out of these 4 values is the lowest value? Obviously the two with the 6 in the thousandths place are more expensive than the ones with the 5s in the thousandths place, so that already eliminates Brand Z and Brand W.

What do we have left?

<span>Brand X: 1.27/200=.00635
</span><span>Brand Y: .62/100 =.0062
</span> Cool. Which of these is a smaller number? Tip: If the first number besides 0 is the same, check the next one! You should get that Brand Y is the cheapest! :) Hoped this helped!

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Is y= |x|-1 a linear equation

natita [175]

Answer:

y=x-1

Step-by-step explanation:

those lines by the x are absolute value lines and the absolute value of x is x so the equation basically stays the same

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4 years ago

During a trip, a driver travelled a distance of 80km at an average speed of 60km/hr.He then changed his speed and travelled the

oksian1 [2.3K]

Answer:

50 km/hr

Step-by-step explanation:

D = RT

Time for first part of trip = 80/60 = 4/3 hr.

Time for second part of trip = 20/30 = 2/3 hr.

total time for entire trip = 4/3 + 2/3 = 6/3 = 2 hr.

Total distance = 100 km

Average rate of speed for entire trip = 100/2 = 50 km/hr

4 0

3 years ago

A random sample of 100 people from City A has an average IQ of 120 with a SD of 18. Independently of this, a random sample of 15

Sloan [31]

Answer:

$z=\frac{(120-116)-0}{\sqrt{\frac{18^2}{100}+\frac{15^2}{150}}}}=1.837$

$p_v =P(z>1.837)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the average IQ on city A is signficantly higher than city B at 5% of singificance.

Step-by-step explanation:

$\bar X_{A}=120$ represent the mean for sample 1

$\bar X_{B}=116$ represent the mean for sample 2

$s_{A}=18$ represent the sample standard deviation for 1

$s_{B}=15$ represent the sample standard deviation for 2

$n_{A}=100$ sample size for the group 2

$n_{B}=150$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if residents of City A smarter on average, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A} - \mu_{B}> 0$

We don't have the population standard deviation's, but the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{A}-\bar X_{B})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(120-116)-0}{\sqrt{\frac{18^2}{100}+\frac{15^2}{150}}}}=1.837$

P value

Since is a one right tailed test the p value would be:

$p_v =P(z>1.837)=1-P(Z$

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3 years ago

What is 55 subtracted by 65

vivado [14]

Answer:

Step-by-step explanation:

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