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Len [333]
3 years ago
7

Expand log7 (x^3/y)^3

Mathematics
2 answers:
EleoNora [17]3 years ago
5 0

Answer:

b.) 9 log7 x - 3 log7 Y

Step-by-step explanation:

log_{7}\bigg(  \frac{ {x}^{3} }{y} \bigg)^{3}  \\  \\  = 3log_{7}\bigg(  \frac{ {x}^{3} }{y} \bigg)  \\  \\  = 3log_{7} {x}^{3}  - 3log_{7}y \\  \\  = 3 \times 3log_{7} {x}  - 3log_{7}y \\  \\ = 9log_{7} {x}  - 3log_{7}y \\  \\

weqwewe [10]3 years ago
4 0

Answer:

A resposta é a C

Eu com certeza apostaria na c

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igor_vitrenko [27]

Answer:

Side A = 11

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7 0
3 years ago
Please help quickly !
KonstantinChe [14]

Answer:

16.5x = 465.3

Step-by-step explanation:

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4 years ago
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ANTONII [103]

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
What is the value of e^ln7 x1<br> 7e<br> 7x<br> 7
sweet-ann [11.9K]

Answer:

Both answer shown

IF it is

e^{ln 7x}= 7x

OR

IF it is

e^{ln 7}\times 1}=7

Step-by-step explanation:

Given: Little confusion is in the question

e^ln7 x1

i.e e^{ln 7x}

To Find:

e^{ln 7x}= ?

Solution:

We know Logarithmic identity as

\ln e = 1

\ln e^{x} = x

Similarly,

e^{\ln x}=x

IF it is

e^{ln 7x}= 7x

OR

IF it is

e^{ln 7}\times 1}=7\times 1=7

3 0
3 years ago
Read 2 more answers
What is the quotient of a^3b/c^2 / 2ab/c^3 ? Assume a0, b0, and c0. a2c a3bc
kolbaska11 [484]

Answer:

(-6a^3b + 2ab^2)(5a^2 - 2ab^2 - b)

Multiply each term in the first parenthesis by each term in the second parenthesis.

Then combine like terms.

-30a^5b +12a^4b^3 +6a^3b^2 +10a^3b^2 -4a^2b^4 -2ab^3

-30a^5b + 12a^4b^3 +16a^3b^2 - 4a^2b^4 - 2ab^3

LETTER B

5 0
3 years ago
Read 2 more answers
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