Answer:
Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;
Therefore, the shortest distance from the point to the plane is
Answer:
Step-by-step explanation:
Given the simultaneous equation
3x+4y=15. Equation 1
3x-y=30. Equation 2
Using elimination method
Sutract equation 2 from 1
Then, will have
3x-3x+4y--y=15-50. -×-=+
4y+y=-15
5y=-15
Divide Both sides by 5
y=-15/5
y=-3
From equation 2
3x-y=30
3x--3=30
3x+3=30
3x=30-3
3x=27
Divide both side by 3
x=27/3
x=9
Then, x=9 and y=-3
Answer:
£320
Step-by-step explanation:
Using proportion,
If 110% = £352
100% = ?
= 
= £320
Answer: Ooh, okay. Have fun then I guess.
