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WINSTONCH [101]
3 years ago
13

What is the equation of the circle center (0, 3) and radius 4?

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
5 0

\huge{ \mathfrak{  \underline{ Answer }\:  \:  ✓ }}

The equation of the circle is represented as :

\hookrightarrow (x - h) {}^{2}  + (y - k) {}^{2}  = (r) {}^{2}

where, h is x-coordinate and k is y-coordinate of center of the circle, and "r" is radius of the given circle.

Therefore, the equation of the above circle will look like :

\hookrightarrow(x - 0) {}^{2}  + (y - 3) {}^{2}  =  {4}^{2}

\hookrightarrow {x}^{2}  + (y - 3) {}^{2}  = 16

_____________________________

\mathrm{ ☠ \: TeeNForeveR \:☠ }

Sunny_sXe [5.5K]3 years ago
3 0

Answer:

( x )² + ( y - 3 )² = 16

Step-by-step explanation:

The general format for circular equations is ( x - a )² + ( y - b )² = r²

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If you save $125 each week for one year, how much will you be able to save? There are 52 weeks in one year.
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3 years ago
The height of a triangle is two more than three times the base. Determine the dimensions that will give a total area of 28 yards
jonny [76]
H = 3b+2
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⊕\left \{ {{y=2} \atop {x=2}} \right.  \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \beta  \\  \\  \\  x^{2}  \sqrt{x}  \sqrt[n]{x}  \frac{x}{y}  x_{123}  x^{123}  \leq  \geq  \pi  \alpha   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  x_{123}  \int\limits^a_b {x} \, dx  \left \{ {{y=2} \atop {x=2}}
ω
 l
∩
8 0
3 years ago
Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
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