Question

What is the equation of the circle center (0, 3) and radius 4?

Answer 1

$\huge{ \mathfrak{ \underline{ Answer }\: \: ✓ }}$

The equation of the circle is represented as :

$\hookrightarrow (x - h) {}^{2} + (y - k) {}^{2} = (r) {}^{2}$

where, h is x-coordinate and k is y-coordinate of center of the circle, and "r" is radius of the given circle.

Therefore, the equation of the above circle will look like :

$\hookrightarrow(x - 0) {}^{2} + (y - 3) {}^{2} = {4}^{2}$

$\hookrightarrow {x}^{2} + (y - 3) {}^{2} = 16$

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Answer 2

Answer:

( x )² + ( y - 3 )² = 16

Step-by-step explanation:

The general format for circular equations is ( x - a )² + ( y - b )² = r²