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anzhelika [568]
3 years ago
8

Y = 3x -3.x - y = -24 solve by substitution

Mathematics
1 answer:
IRISSAK [1]3 years ago
8 0
-3x -(3x) = 24
-6x = 24
x= -4

y= 3(-4)
y=-12
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In the figure below, what is the area of triangle ABC?
Serhud [2]
The area of a triangle is base * height / 2

The length of the base is 16 - 12 = 4

The height is 31 - 0 =0

Then the area is 4*31/2 = 62
5 0
3 years ago
Consider this equation. cos(θ)= -3/10 If θis an angle in quadrant II, what is the value of tan (θ)?
Alja [10]

Answer:

C)

Step-by-step explanation:

Trigonometry ratio:

         \sf Cos \ \theta = \dfrac{Adjacent \ side}{hypotenuse}=\dfrac{-3}{10}

We need to find the opposite side using Pythagorean theorem.

 opposite side² = hypotenuse² - adjacent side²

                           = 10² - (-3)²

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                           = 91

opposite side    = √91

                 \sf tan \ \theta = \dfrac{opposite \ side}{adjacent \ side}

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In quadrant II, value of tan \theta is negative.

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7 0
2 years ago
Which of the following is true given the inequality below?
ra1l [238]

Answer:

D. is to the right of -0.9 on the horizontal number line

Step-by-step explanation:

The given inequality is - \frac{4}{5} > - 0.9 i.e. - 0.8 > - 0.9 .......... (1)

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3 0
3 years ago
Find x inscribed angles
mina [271]
The easiest variable you can solve for first is "z". Knowing that opposite angles of a quadrilateral inscribed in a circle are supplementary, subtract 93 from 180 to get z.
Z should equal 87.
The next variable we can solve for is "x". We know that inscribed angles are half the measure of their intercepting arc, so we know 93 is half of (112 + x). The equation would look like this:

93= (112 + x)/2
Multiply both sides by 2
186 = 112 + x
Subtract 112 from both sides
74 = x

Now we can apply the same method we used to find "x" to find y. Set up an equation like this:
80 = (y + x)/2
Substitute the value of x in
80 = (y + 74)/2
Multiply both sides by 2
160 = y + 74
Subtract 74 from both sides
86 = y

Hope this helps!
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%283x-1%29%5E%7B2%7D%20%2B%2012x-4%3D0" id="TexFormula1" title="(3x-1)^{2} + 12x-4=0" alt="(3x
kaheart [24]
Your answer is x = 1/3 or x = -1
To solve I would start by expanding the bracket and then collecting like-terms, and then re-factoring:
(3x - 1)² + 12x - 4 = 0
9x² - 6x + 1 + 12x - 4 = 0
9x² + 6x - 3 = 0
3(3x² + 2x - 1) = 0
From here you can factorise the bracket even further:
3(3x - 1)(x + 1) = 0
Then divide by 3:
(3x - 1)(x + 1) = 0
3x - 1 = 0
x = 1/3

x + 1 = 0
x = -1
I hope this helps! Let me know if you have any questions :)
6 0
4 years ago
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