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hodyreva [135]
3 years ago
8

Practice:

Mathematics
1 answer:
Andrew [12]3 years ago
4 0

omg that was hard I see that in my module to

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What is the slope of (0,1) and (5,4)
mote1985 [20]

Answer:

3/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-1)/(5-0)

m=3/5

3 0
4 years ago
Under what operations are the set of integers closed? Explain your answer. UPDATE ANSWER IS
stich3 [128]

Answer:

see below

Step-by-step explanation:

Closed under addition, subtraction and multiplication

Not closed under division :-

for example  3/4 = 0.75 which is not an integer

8 0
4 years ago
Read 2 more answers
What is the coefficent of 3/4 y
Alexxx [7]

Answer:

Step-by-step explanation:

4 0
2 years ago
Solve the equation x = 5/3 (pie) (r^3) for r.
DENIUS [597]

Answer and Step-by-step explanation:

To solve for r, we need to get everything away from r. We can start off by moving five thirds, and pi.

x = \frac{5}{3} \pi r^{3}

Multiply each side by \frac{3}{5}, then divide by \pi (pi)

\frac{3x}{5\pi }  = r^{3}

Now, take the cubed root of both sides.

\sqrt[3]{\frac{3x}{5\pi } }  = r

^^ That is the answer.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

3 0
3 years ago
Determine whether each table below models a linear, quadratic or exponential function.
Virty [35]
The <u>correct answers</u> are:

The <u>first table is linear</u>.
The <u>second table is exponential</u>.

Explanation:

To see if a set of data is linear, we find the <u>slope</u>.  Slope is given by the formula

m=\frac{y_2-y_1}{x_2-x_1}.

We check each pair of points in the <u>first table</u>.  The slope between the <u>first two points</u> is:
m=\frac{1-4}{6-5}=\frac{-3}{1}=-3.

The slope between the <u>second two points</u> is:
m=\frac{-2-1}{7-6}=\frac{-3}{1}=-3

The slope between the <u>third two points</u> is:
m=\frac{-5--2}{8-7}=\frac{-5+2}{8-7}=\frac{-3}{1}=-3

Since the slope is the <u>same </u>between any two pairs of points, this is a <u>linear </u>set of data.

Checking each pair of points in the <u>second table</u>, we have:
m=\frac{1-0}{6-5}=\frac{1}{1}=1 for the <u>first two points</u>.

For the <u>second pair of points</u>, we have:
m=\frac{4-1}{7-6}=\frac{3}{1}=3

Since the slope is <u>not the same</u> between each pair of points, we know the data is <u>not linear.</u>

Next we will check the <u>second table</u> to see if it is <u>quadratic</u>.  Since the x-coordinates go up the same number each time, we can check the y-coordinates, specifically looking at the <u>second differences</u>.

For the <u>second differences</u>, we first find the difference between each y-value:
1-0=1
4-1=3
8-4=4

Now we find the <u>difference between each first difference</u>:
3-1=2
4-3=1

Since these second differences are <u>not the same</u>, the data is <u>not quadratic</u>.

From <u>graphing </u>the data in the table, we can see that the data in the second table is <u>exponential</u>.

7 0
4 years ago
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