A helicopter is hovering 110 feet in the air over a landing pad. If a man sees the helecopter at an angle of elevation of 29°, w
hich of the following shows how far the man is from the helicopter landing pad?
1 answer:
See the attached figure to better understand the problem
we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
the answer is
the man is 198.45 ft from the helicopter landing pad
we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
the answer is
the man is 198.45 ft from the helicopter landing pad
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Step-by-step explanation:
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(3x - 1) = 15
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4x + 4 - 3x + 1 = 60
x + 5 = 60 ( subtract 5 from both sides )
x = 55