Answer: A
We could solve it but it's easier to just check the given solutions.
A. (7,1)
2y + 5 = 2(1)+5 = 7 = x, good
x/3-y = 7/3 - 1 = 4/3, good
B. (-3,8)
2y + 5 = 2(8)+5 = 21 not x=-3, doesn't check
C. Can't be true because we found a solution
D. Infinitely many solutions not true because the lines have different slopes
So hmm check the picture below
the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)
thus
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}\qquad \begin{cases} h=height\\ r=radius\\ ------\\ h=2(2r) \end{cases}\implies V=\cfrac{\pi r^2[2(2r)]}{3} \\\\\\ V=\cfrac{4\pi r^3}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ah%3Dheight%5C%5C%0Ar%3Dradius%5C%5C%0A------%5C%5C%0Ah%3D2%282r%29%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%5B2%282r%29%5D%7D%7B3%7D%0A%5C%5C%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D)
<u>Given:</u>
1. Children ticket = $11 , Adult ticket = $16
2. Total tickets sold = 150
3. Total revenue = $2250
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<u>Assumed all sold are children tickets:</u>
total revenue = 150 x 11 = $1650
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<u>Difference in revenue:</u>
$2250 - $1650 = $600
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<u>Difference in the price of two tickets:</u>
$16 - $11 = $5
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<u>Find number of adult tickets:</u>
Number of adult tickets = $600 ÷ $5 = 120
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<u>Find number of children tickets:</u>
Number of children tickets = 150 - 120 = 30
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Answer: Adult tickets = 120, Children tickets = 30
Let x be the number of days and y represent miles driven.
Since it costs 25 per day, you multiply 25 by x.
25x
10 cents (otherwise known as .1 dollars) per mile, multiply .1 times y. Now add the two.
.1y
25x+.1y
The answer is <span>a.) 25x + 0.1y</span>.
Answer:
Find the slant height of a cone with surface area 381.77 ft² and radius 6.2 ft.
O = pi·r^2 + pi·r·s --> s = O/(pi·r) - r = 381.77/(pi·6.2) - 6.2 = 13.40 ft
Find the height of a square pyramid with volume 96 m³ and dimensions of base are 9 m by 9 m.
V = 1/3·a^2·h --> h = 3·V/a^2 = 3·96/9^2 = 32/9 = 3.556 m
Find the height of a cone with volume 4034.66 cm³ and radius 13 cm.
V = 1/3·pi·r^2·h --> h = 3·V/(pi·r^2) = 3·4034.66/(pi·13^2) = 22.80 cm
Find the length of the radius of a sphere with a surface area of 5541.77 cm².
O = 4·pi·r^2 --> r = √(O/(4·pi)) = √(5541.77/(4·pi)) = 21.00 cm
