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Vlad [161]
3 years ago
11

A group of students wants to find the diameter of the trunk of a young sequoia tree. The students wrap a rope around the tree tr

unk
Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:

the length of the rope gives the circumference of the tree trunk. the tree trunk is in the shape of a circle. the circumference of a circle = πD. the inches would be converted to foot and the diameter would be determined from the length of the  rope.

7 foot

Step-by-step explanation:

Here is the full question :

A group of students wants to find the diameter of the trunk of a young sequoia tree. The students wrap a rope around the tree trunk. the length is 21 feet 8 inches

Explain how they can use the length to determine the diameter of the tree trunk to the nearest half foot

What is the diameter of the tree trunk

the circumference of a circle = πD

π = 22/ 7

D = diameter

we need to convert 21 feet 8 inches to foot

1 inch = 0.0833333 foot

8 x 0.0833333 = 0.667

0.667 + 21 = 21.667 foot

21.667 = 22/7 x diameter

diameter = 21.667 x 7/22 = 6.89 foot

The nearest half foot of 6.89 is 7.

7 foot

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Answer:

[11.5-(2.5*3)]^2=16

Step-by-step explanation:

We want to evaluate [11.5-(2.5*3)]^2

Let us evaluate within the parenthesis first:

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\implies [11.5-(2.5*3)]^2=[11.5-7.5]^2

We again subtract within the bracket to obtain:

[11.5-(2.5*3)]^2=[4]^2

This finally gives us:

[11.5-(2.5*3)]^2=16

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Answer:

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Step-by-step explanation:

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