-Find the sum or difference

Create an equation to represent the situation below and then solve your equation.

bija089 [108]

I don't know the answer

3 0

3 years ago

Simplify (2m^6)^3.

labwork [276]

Answer:

B. 8m ^ 18

Step-by-step explanation:

(2m ^6)^3 is the same as ;

(2 ^1 × m ^ 6) ^ 3.....multiply the powers 1 and 6 by 3

2 ^ (1×3) × m ^ (6×3).....this equals;

2 ^ 3 × m ^ 18

8m^18

hope this helps :)

8 0

3 years ago

Read 2 more answers

Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on

boyakko [2]

Answer:

Mathew invested $600 and $2400 in each account.

Solution:

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest $(I_1)$ earned in first account for one year,

$\text {simple interest}=\frac{\text {pnr}}{100}$

Where

p = amount invested in first account

n = number of years

r = rate of interest

hence, by using above equation we get $(I_1)$ as,

$I_{1}=\frac{P \times 1 \times 3}{100}$ ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest $(I_2)$ earned in second account,

$I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2$

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

$I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3$

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

$I = I_1+ I_2 ---- eqn 4$

By substituting eqn 1 , 2, 3 in eqn 4

$\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}$

$\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}$

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600

Hence, Mathew invested $600 and $2400 in each account.

3 0

3 years ago

Read 2 more answers

Can someone please help me with 9 and 10!!! Thank you so much!!!

Dmitrij [34]

9 Is −4x3 and 10 is −5a2

5 0

3 years ago

Your neighbor has decided to enlarge his garden. The garden is rectangular with width 6 feet and length 15 feet. The new garden

Nana76 [90]

Answer:

Original garden: 42 feet

Enlarged garden: 98 feet

Step-by-step explanation:

Perimeter = length (2) + width (2)

Original perimeter:

P = 15(2) + 6(2)

P = 30 + 12

P = 42 feet

In this problem, similar is proportional, so the new garden will be proportional to the old one.

If the original length was 15 and the new length is 35, then 15 would have had to have been multiplied by 2 1/3. That means you need to multiply 6 by 2 1/3, which is 14. That means the dimensions of the enlarged yard is 14 (width) × 35 (length).

Enlarged perimeter

P = 35(2) + 14(2)

P = 70 + 28

P = 98 feet

4 0

4 years ago