Which of the following answers is the value of x in this equivalent fraction?

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

7 0

I just had the question and the correct answer is 36.

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Answer this question to get marked as barinliest!!!!!

kap26 [50]

Here’s the answer and working out. Hope it helps

6 0

3 years ago

Lara went to the nursery and spent $140 she purchased 4 plants each of the plant costs the same price what is the cost of 1 plan

trapecia [35]

Answer:

$35 per plant

Step-by-step explanation:

You take the 140 and divide that by 4 to get your answer.

8 0

2 years ago

Please help NO LINKS

inn [45]

Answer:

(5,-6)

Step-by-step explanation:

This is where the two lines meet. I hope this helps ◕ ◡ ◕

5 0

2 years ago

Read 2 more answers

a manufacturer is designing a flashlight for the flashlight to admit a focused beam the bull needs to be on the central axis of

Helen [10]

Answer:

y= 1/12(x-0)^2+0

this answer works as an upward parabola

Step-by-step explanation:

The formula for a veritcal parabola is y=1/4p(x-h)^2+k
(h,k)= coordinates of the vertex of the parabola
p= absolute value of the distance from the vertex to the focus/directrix
In this problem, it is given that the vertex is at the origin (0,0) and the focus (the bulb), is 3 centimeters away from the vertex.
Now, you know the values of the variables. Fill in the values
FROM THE FORMULA: 1/4p turns into 1/12 since p is 3.
(x-h)^2+k turns into (x-0)^2+0, since h and k where the values of the vertex which was 0,0
once all the variables are given values (except x and y) you have made your equation!
The answer is y=1/12(x-0)^2+0

MARK BRAINLIEST! this took forever, and I know this is the right answer since I got a perfect grade when I turned mine in.

8 0

3 years ago

Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0

3 years ago