sum of two angles of triangle are equal to the exterior angle of triangle
Answer:
Step-by-step explanation:
It's algebra really, basically make a system of equations.
1b+5j=t
3b+2j=2t
I'm gonna solve the first one for buckets so we have it in terms of jars.
b+5j=t
b=t-5j
Now I plug that into the other equation
3b+2j=2t
3(t-5j)+2j=2t
3t-15j+2j=2t
Now, since it wants how many jars are in one tub, I want to solve it so there's 1t on one side of the equation and all js on the other. or it other words solve for t.
3t-15j+2j=2t
3t-13j = 2t
3t = 2t+13j
t = 13j
So it takes 13 jars to make one tub, or one jar is 1/13 of a tub. You could then plug that in to one of the equations and find how much a bucket is.
Answer: the 2nd and the 5th one
Step-by-step explanation:
Just substitute it into the gradient formula which is: y2 - y1 / x2 - x1. So 2-3/2-9 = -1/-7 = 1/7
Part A: To find the lengths of sides 1, 2, and 3, we need to add them together. We can do this by combining like terms (terms that have the same variables, or no variables).
(3y² + 2y − 6) + (3y − 7 + 4y²) + (−8 + 5y² + 4y)
We can now group them.
(3y² + 4y² + 5y²) + (2y + 3y + 4y) + (-6 - 7 - 8)
Now we simplify
12y² + 9y - 21
Part B: To find the length of the 4th side, we need to subtract the combined length of the 3 sides we know from the total length (perimeter).
(4y³ + 18y² + 16y − 26) - (12y² + 9y - 21)
Simplify, subtract like terms.
4y³ + (18y² - 12y²) + (16y - 9y) + (-26 + 21)
4y³ + 6y² + 7y - 5 is the length of the 4th side.
Part C (sorry for the bad explanation): A set of numbers is closed, or has closure, under a given operation if the result of the operation on any two numbers in the set is also in the set.
For example, the set of real numbers is closed under addition, because adding any two real numbers results in another real number. Likewise, the real numbers are closed under subtraction, multiplication and division (by a nonzero real number), because performing these operations on two real numbers always yields another real number.
<em>Polynomials are closed under the same operations as integers. </em>
