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wariber [46]
3 years ago
13

Write an algebraic expression. 9 1/2 less then the product of 7 and a number Y

Mathematics
2 answers:
Leto [7]3 years ago
7 0

Answer:

7y-9.5

Step-by-step explanation:

I think this is correct :)

qaws [65]3 years ago
7 0

Answer:

Step-by-step explanation:

Product of 7 and number y = 7y

9 1/2 less than product of 7 and number y = 7y - 9 1 /2

= 7y - 19/2

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How would you find the square root of a number? How would you use it?
NeTakaya
A square root is a number times itself .
for example 2x2 is a square root .
so, any number times itself is a square root
4 0
4 years ago
Y = -2/3x + 4
kari74 [83]

Answer:

(-4, 6.667) x=-4 y=6.667

I hope this helps!

6 0
3 years ago
30 POINTS! Please help with this goemtery question.
n200080 [17]

Answer:

(28*12)-(18*5) or 246 meters squared

Step-by-step explanation:

It is actually easy really, all you have to do is find the area of the larger polygon (28*12) or 336 and subtract the smaller polygon (18*5) or 90 and subtract it from the larger polygon getting you 246 meters squared

3 0
4 years ago
Which function has a simplified base of 4^3√4?
IrinaVladis [17]

Answer:

The function is f(x) = 4(\sqrt[3]{16} )^{2x}.

Step-by-step explanation:

We have to choose from options the exponential function which has a simplified base of 4∛4 i.e. ∛(256).

Now, the exponential function in the option III will be the answer.

The function is f(x) = 4(\sqrt[3]{16} )^{2x}.

So, the base is (\sqrt[3]{16} )^{2} = \sqrt[3]{16^{2}} = \sqrt[3]{256} = 4\sqrt[3]{4}. (Answer)

The general formula of an exponential function is f(x) = a(b)^{x} , where b is called the base of the function.  

4 0
3 years ago
Can i have some help
Andrews [41]

Answer: g(x) = 3/2 x + 9

Step-by-step explanation:

h(x) = -2/3 x - 1

perpendicular lines always have the opposite sign, reciprocal slope

so, the slope of the perpendicular line would be: m = 3/2

y = mx + b

y = 3/2 x + b

plug in (-4, 3) to find b

3 = 3/2 (-4) + b

3 = -6 + b

b = 9

y = 3/2 x + 9

g(x) = 3/2 x + 9

5 0
3 years ago
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