Answer:
A(n) = 100(1.1)^n
Step-by-step explanation:
Given that :
Account balance = A(n)
Compound interest paid = 10%
We need to obtain the initial amount deposited, that is A(n), when n = 0
In year, n = 1
Account balance, A(n) = $110
Let initial deposit = P
Hence,
Compound interest relation should be ;
A(n) = P(1 + r)^n
Plugging in our values
110 = P(1 + 0.1)^1
110 / P = 1.1^1
110/P = 1.1
110 = 1.1P
P = 110 / 1.1
P = 100
Hence, we can define the amount paid inn n years by substuting the value of P into the compound interest formula :
A(n) = 100(1 + 0.1)^n
A(n) = 100(1.1)^n
What you would do is multiply for this problem.
you turn 35% into a decimal so the problem would look like
0.35 x 120 that should equal 42
hope that helps
Answer: X = y - yi - 7i
Y = (x + 7i)/(1 - i)
Step-by-step explanation: for the case of (X) you only need to pass the 7i to the other side with the subtraction sign (-7i), then we get this equation:
x + 7i = y − yi
X = y - yi - 7i
in the case of the (Y), first we select the common multiple.
y - yi = y(1 - i)
if we replace it in the original expression, we get the following equation:
x + 7i = y(1 - i)
after that you can pass the value (1 - i) to the other side dividing,
Y = (x + 7i)/(1 - i)
1.5
2.3
3.6
4.15
5.15
i know im right trust me
After 1st year: 250$:100%=x$:116%, 250$*116%=x$*100%, x=(250*116)/100=290$. After 1st year I will have 290$
After 2nd year: 290$:100%=x$:116%, x=(290*116)/100=336.4$. After 2nd year I will have 336.4$
After 3rd year I will have (336.4*116)/100=390.224$
After 4th yr: (390.224*116)/100=452.65984$
After 5th yr: (452.65984*116)/100=525.085$
After- 6th yr: 609.1$, 7th yr: 706.556$, 8th yr: 819.605$, 9th yr: 950.742$
10th yr: 1102.86$, 11th yr: 1279.32$, 12th yr: 1484.01$, 13th yr: 1721.45$,
14th yr: 1996.88$, 15th: 2316.38$, 16th yr: 2687$, 17th yr: 3116.92$
After 18 years I will have 3615.63$.
