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kkurt [141]
3 years ago
15

What is the GCF of 18 and 25?

Mathematics
2 answers:
kozerog [31]3 years ago
5 0

Answer:

1

Step-by-step explanation:

Rom4ik [11]3 years ago
4 0

Answer:

It's 1. If I'm not mistaken. :)

Step-by-step explanation:

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A point moves along the curve y = √ x in such a way that the y-component of the position of the point is increasing at a rate of
Eduardwww [97]

Answer:

The value of x component changes at a rate of \frac{dx}{dt}=4\sqrt{x} units per second

Step-by-step explanation:

We are given that y=x^{\frac{1}{2}}

Differentiating on both sides with respect to time we get

\frac{dy}{dt}=\frac{d\sqrt{x}}{dt}\\\\\frac{dy}{dt}=\frac{1}{2}x^{\frac{-1}{2}}(\frac{dx}{dt})\\\\\frac{dy}{dt}=\frac{1}{2\sqrt{x}}\frac{dx}{dt}

It is given that \frac{dy}{dt}=2units/sec

Solving for \frac{dx}{dt} we get

\frac{dx}{dt}=\frac{dy}{dt}\times 2\sqrt{x}\\\\\frac{dx}{dt}=4\sqrt{x}

5 0
2 years ago
Y varies directly as x if x=15 when y=20, find x when y=30
mixas84 [53]

Answer:

X=22.5

Step-by-step explanation:

Y=kX

20=15k

k=4/3

For X when Y=30

30=4/3×X

Cross multiply

4X=90

X=22.5

6 0
2 years ago
Start solving the following x+5=11
dimulka [17.4K]

Answer:

6

Step-by-step explanation:

x=11-5=6

therefore x=6

6 0
2 years ago
Read 2 more answers
A horse had 4 1/5 scoops of oats in his bucket. He ate 2 1/2 scoops of oats. How much scoops of oats are left in his bucket? Ent
lidiya [134]

Answer:

1 7/10

Step-by-step explanation:

4 1/5-2 1/2 = 17/10 = 1 7/10

8 0
3 years ago
Read 2 more answers
A converging lens of focal length 5 cm is placed at a distance of 20
lesya [120]

The object should be placed 20/cm from the lens so as to form its real image on the screen

<h3>Mirror equation</h3>

The mirror equation is given according to the expression below;

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

Given the following parameters

f = 5cm

v = 20cm

Required

object distance u

Substitute

1/5 = 1/u +1/20

1/u = 1/5-1/20
1/u = 3/20

u = 20/3 cm

Hence the object should be placed 20/cm from the lens so as to form its real image on the screen

Learn more on mirror equation here; brainly.com/question/27924393

#SPJ1

4 0
1 year ago
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