The deliberate termination of a human pregnancy, most often performed during the first 28 weeks of pregnancy.
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
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Answer:
paraell
Step-by-step explanation:
Answer:
-6 33/40
Step-by-step explanation:
2 5/8 * -2 3/5
Change each to an improper fraction
2 5/8 = (8*2+5)/8 = 21/8
2 3/5 = (5*2+3)/5 = 13/5
21/8 * -13/5
-273/40
Change to mixed number
40 goes into 273 6 times
6*40 = 240 273-240 =33
-6 33/40
Step-by-step explanation:
The value of b will be 43° as it is vertically opposite angle.. !!