You get 2m+m-3n which simplifies to 3m-3n
Answer:
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Step-by-step explanation:
area of rrctangle:
12×8= 96cm²
now if rectangle dissapears and then we "glue" what's left, we gonna get two circles
area of circle which gas diameter of 12cm( so radius will be 6cm)will be
πr²=36π≈113.04
another circles radius is 4cm,so area is:
16π≈50.25
sum of all areas: S≈96+113.04+50.25≈259.28cm2
Answer:
your work is not clearly taking sorry i can't see
Answer:
Step-by-step explanation:
Perimeter of rectangle = 208 m
2*(l + w) = 208 {divide both sides by 2}
l +w = 208/2
l +w = 104
l = 104 - w
Area of rectangle = 2415 square meters
l*w = 2415
Substitute l = 104 - w in the above equation,
(104 - w ) *w = 2415
104w - w² = 2415
0 = 2415 - 104w + w²
w² - 104w + 2415 = 0
Sum = -104
Product = 2415
Factors = (-69) , (-35)
w² - 35w - 69w + (-69)*(-35) = 0
w(w - 35) - 69(w - 35) = 0
(w -35)(w -69)
w - 35 = 0 ; w -69 = 0
w = 35 ; w = 69
The dimensions of the building: 35 , 69
