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Ne4ueva [31]
3 years ago
13

Describe the relationship between integers andrational numbers.​

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
4 0

A rational number is that number that can be expressed as a ratio between two integers. Thus integers are also rational numbers: ex: 7=7/1=14/2, 5=-5/(-1)=5/1=15/3,....

Examples of rational numbers: 1/5, 2/3, -5/7, etc

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Answer the following function, algebra 1.
11111nata11111 [884]

Answer:

g(f(x)) = 1x² + 1

Step-by-step explanation:

We are given:
f(x) = x² - 1

g(x) = x + 2

And we want to find g(f(x)).

To do this, we substitute f(x) as x in x+2 (the expression that is equal to g(x)), as g(f(x)) is saying that f(x) is the value of x in g(x).

So, this will be:

g(f(x)) = x² - 1 + 2

Simplify

g(f(x)) = x² + 1

In your system, place 1 in front of x² - this is the coefficient of x², and also 1 after that - this is a constant.

4 0
1 year ago
Which expressions is equivalent to 4(x+1)-2(x-2)
Y_Kistochka [10]
(4x+4)-(2x-4) would be an equivalent expression.
8 0
2 years ago
Read 2 more answers
The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature
Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}

Where

(t) = \ time

T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)

T_{s} = Surrounding \ temperature

T_{0} = Initial \ temperature \ of \ the \ body

k = constant

From the question,

T_{0} = 86 ^{o}C

T_{s} = -20 ^{o}C

∴ T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C

T_{0} - T_{s} = 106^{o} C

Therefore, the equation T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt} becomes

T_{(t)}=-20+106 e^{kt}

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time t = 1 \ hour, T_{(t)} = 58^{o}C

Then, we can write that

T_{(1)}=58 = -20+106 e^{k(1)}

Then, we get

58 = -20+106 e^{k(1)}

Now, solve for k

First collect like terms

58 +20 = 106 e^{k}

78 =106 e^{k}

Then,

e^{k} = \frac{78}{106}

e^{k} = 0.735849

Now, take the natural log of both sides

ln(e^{k}) =ln( 0.735849)

k = -0.30673

This is the value of the constant k

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at t = 2 \ hours

From

T_{(t)}=-20+106 e^{kt}

Then

T_{(2)}=-20+106 e^{(-0.30673 \times 2)}

T_{(2)}=-20+106 e^{-0.61346}

T_{(2)}=-20+106\times 0.5414741237

T_{(2)}=-20+57.396257

T_{(2)}=37.396257 \ ^{o}C

T_{(2)} \approxeq  37.40 \ ^{o}C

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0
2 years ago
Read 2 more answers
if the machine can process 600 pretzels 15 minutes how long must the machine run in order to make 3120​
kati45 [8]
78


step by step explanation:

first: divide 600 and 15

answer to 600/15: 40

second: divide 3120 and 40

final answer: 78
5 0
3 years ago
A board measures 4 yards, 2 feet, and 6 inches. What is its length in feet?
never [62]
Well think about it .... 1 yard = 3 ft so you'd do 3 times 4 1 foot = 12 inches so it'd be half of a foot
7 0
2 years ago
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