I recommend to read whatever the person above said
Answer:
Yes, it will reach or exceed 141 degree F
Step-by-step explanation:
Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

Suppose T = 141°F,



Since, a quadratic equation
has,
Real roots,
If Discriminant, 
Imaginary roots,
If D < 0,
Since, 
Thus, roots of -0.005x² + 0.45x + 125 are real.
Hence, the temperature can reach or exceed 141 degree F.
Answer:
Step-by-step explanation:
<u>Given:</u>
<u>Length is:</u>
<u>Substitute values and solve for w:</u>
- 500 = 2*120 + 2w
- 2w = 500 - 240
- 2w = 260
- w = 260/2
- w = 130 m
Answer:
- C = 0.97m
- $1164 for 1200 miles
- 845 miles for $820
Step-by-step explanation:
Given a car's cost of operation is $485 for 500 miles, you want an equation relating cost for m miles, and solutions to that equation for 1200 miles, and for a cost of $820.
<h3>Cost per mile</h3>
The cost per mile is found by dividing the cost by the associated number of miles:
$485/(500 mi) = $0.97 /mi
<h3>Equation</h3>
The equation for the cost will show the cost as the cost per mile multiplied by the number of miles:
C = 0.97m . . . . . where C is cost in dollars for m miles driven
<h3>1200 miles</h3>
The cost for driving $1200 miles will be ...
C = 0.97(1200) = $1164
The cost of driving 1200 miles is $1164.
<h3>$820</h3>
The number of miles that can be driven for a cost of $820 is ...
820 = 0.97m
m = 820/0.97 = 845.36
About 845 miles are driven for a cost of $820.
Answer:
Step-by-step explanation:
(1)
a1=-2
r=-2
