Answer:
the answer might be either one of the four
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Answer:
D.
Vertex form: f(x) = 2/3(x + 3)^2 - 6.
Standard form: f(x) = 2/3x^2 + 4x.
Step-by-step explanation:
The vertex is at (-3, -6) so the vertex form is
y = a(x - (-3))^2 - 6
y = a(x + 3)^2 - 6
Now we find the value of a by substituting x = 0 and y = 0:
0 = a(0 + 3)^2 - 6
9a = 6
a = 2/3.
Vertex form is y = 2/3(x + 3)^2 - 6.
Convert to Standard form:
Multiply through by 3:
3y = 2(x + 3)^2 - 18
3y = 2x^2 + 12x + 18 - 18
3y = 2x^2 + 12x
y = 2/3x^2 + 4x.
