Ask question

Ask question

All categories

3 years ago

9

Bharat has two identical ink pens with full ink. He used 3/4th of the ink from the first pen and 2/3rd of the ink from the secon

d pen. What is the fraction of the ink remaining in the two pens together?

1 answer:

Leno4ka [110]3 years ago

3 0

Answer:

0.58333333333 Or 0.58333333333/100000000000

Step-by-step explanation:

You might be interested in

The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend

spayn [35]

Answer:

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

Step-by-step explanation:

The other addend is determined by subtracting $-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5$ from $10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2$ :

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)$

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5$

$x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

$x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

6 0

3 years ago

Subtract and simplify. Show work please!

ra1l [238]

1) Final expression: $+7y^2-6y-17$

2) Final expression: $21x^3-46x^2+59x-30$

Step-by-step explanation:

1)

The first expression is

$(-2y^2-11y-7)-(-9y^2-5y+10)$

First, we remove the 2nd bracket by changing the sign of all the terms inside:

$-2y^2-11y-7-+9y^2+5y-10$

Now we group the terms with same degree together:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)$

Now we solve the expression in each brackets:

$(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17$

So, this is the final expression.

2)

The second expression is

$(7x-6)(3x^2-4x+5)$

We apply the distributive property, so we rewrite the expression as follows:

$(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)$

Solving both brackets,

$7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30$

Now we group terms of same degree together:

$21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30$

And solving each bracket,

$21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30$

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0

3 years ago

If you use the addition property of equality , what number would you add to both sides of the equal sign to isolate the variable

kkurt [141]

Answer:

The answer is " $\frac{26}{7}$ "

Step-by-step explanation:

The whole question can be found in the file attached.

$\to x + \frac{5}{7} = \frac{31}{7}\\\\$

Subtracting the $\frac{5}{7}$ from both sides of the equations:

$\to x +\frac{5}{7} - \frac{5}{7} = \frac{31}{7} - \frac{5}{7} \\\\$

$= \frac{31-5}{7} \\\\= \frac{26}{7} \\\\$

5 0

3 years ago

What is the equation of a line that is parallel to −3x+4y=4 and passes through the point (4,0)?

Genrish500 [490]

So you have to first put put the equation in slope-intercept form.
-3x+4y=4
+3x +3x
_______________
4y=4+3x
then you divide 4 by 4 and then divide 3x by 4 and you should get y=1+3/4x
then you plug in x and only x so that you can find y and then do the same once you find y
y=1+ (4)3/4
y= 1+3
y=4
then plug in y and solve for x
4= 1+ 3/4x
subtract 1 from both sides
3=3/4x
divide both sides by 3/4
and x=4
so then you find b and put it all in a equation.

3 0

3 years ago

Write the expression-3x2+2y2+5xy-2y+5x2-3y2 in simplest form A how many terms are in the simplified expression? B how many terms

Misha Larkins [42]

If the twos mean squared...
2x^2-y^2+5xy-2y

4 terms

3 0

3 years ago

Read 2 more answers