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Schach [20]
3 years ago
5

Does anyone go to watkins, its in texas

SAT
2 answers:
CaHeK987 [17]3 years ago
6 0
Answer:

Nope

I’m not from Texas nor do I live there so I haven’t
Dmitrij [34]3 years ago
3 0
Answer
Nope
Explanation
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During crawfish season, Xavier sells crawfish for $62.50 per sack and charges a $20.00 delivery fee. Write an equation that coul
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A packing machine at a factory can fill 50 containers of oatmeal every minute. All of the containers filled to the top by this m
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The time taken for the machine to fill 825 containers is 16.5 minutes.

<h3>What is time?</h3>

Time can be defined as the measurable period during which actions, processes, events, or conditions exist. The S.I unit of time is Seconds (s)

To calculate the time taken for the machine to fill 825 containers of oatmeal, we use the formula below.

Formula:

  • R = C/t.................. Equation 1

Where:

  • R = Number container filled by the machine in one minute.
  • C = Total number of containers
  • t = time taken the container

Make t the subject of the equation

  • t = C/R............... Equation 2

From the question,

Given:

  • C = 825 container of oatmeal
  • R = 50 containers of oatmeal per minute

Substitute the values above into equation 2

  • t = 825/50
  • t = 16.5 minutes.

Hence, the time taken for the machine to fill 825 containers is 16.5 minutes.
Learn more about time here: brainly.com/question/17146782

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For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
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The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

Learn more about using the Nernst equation here:

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