The value of m in the Balmer-Rydberg equation is equal to TWO (m= 2). It is part of the Balmer series.
<h3>What is the Balmer series?</h3>
The Balmer series is one of a group of series that describe the spectral line emissions of a hydrogen atom.
The Balmer-Rydberg equation refers to a mathematical equation between spectral lines.
The Balmer-Rydberg equation indicates the wavenumber of the spectrum for hydrogen regarding the Rydberg constant.
The Balmer-Rydberg equation considers the wavelength of the photon, the atomic number and integers indicating spectral lines.
Learn more about the Balmer-Rydberg equation here:
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Answer:
(15/17 = sin ∠ JLK)
(first option listed)
Explanation:
the "sin ∠ JLK" is what we can simply think of as the inside measurement of angle/corner L. (L is the letter in the middle of ∠ JLK , and if you imagine drawing a line from J to L to K, you would see that the only angle you formed both sides of is corner L)
so, we are looking for the sin of L.
(SOH CAH TOA)
we know that
sin = opposite / hypotenuse
However, we do not have the opposite value of this triangle <em>yet. </em>
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we can solve the length of the opposite side with the Pythagorean theorem:
a² + b² = c²
8² + b² = 17²
64 + b² = 289
- 64 - 64
b² = 225
√b² = √225
b = 15
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so, to solve for sin L,
(sin = opposite / hypotenuse)
we should divide the opposite (15) over the hypotenuse (17)
so, 15 / 17 = sin L
(15/17 = sin ∠ JLK)