Answer:
cutting point to minimize total area = 3.39 m
Step-by-step explanation:
Length of wire = 9m
wire is cut into 2 i.e. length of new wires = 4.5 m each
x = 0 ( where the wire will be cut )
Determine the length of wire that will yield minimum total area of figures
<em>i) For equilateral triangle</em>
assume side of triangle = b
length of wire = 9 m
i.e. 3b = 9m hence : b = 9/3 = 3m
area of equilateral triangle = b^2 = 3.89 m^2
when there is no cut the value of x = 9 m
∴ perimeter of triangle = 3b = 9 - x , b = 9 - x / 3
ii) let the radius of circle = c
2πr = 9 ∴ r = 9 / 2π
hence area of circle = πr^2 = 81 / 4π = 6.44 m^2
perimeter of a circle: 2πr = x
∴ r = x / 2π
<em>attached below is the remaining part of the solution</em><em> </em>