Please help ive been stuck on this all day math help pls
1 answer:
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Answer:
Regression Line is given by,
y = 22.909 + 0.209 x
The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Step-by-step explanation:
The equation of Regression equation is of the form of:
y = a + bx
where, a is intercept and b is slope
The formula for a and b is given by,
Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72
Thus, a = 22.909
and b = 0.209
Thus, Regression Line is given by,
y = 22.909 + 0.209 x
Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Now plotting these line:
Answer: (2,1)
Step-by-step explanation:
The two equations given are:
y = 3 -x
y = x - 1
The question is asking to determine the point of intersection for two linear functions aka two lines.
Step #1: Both functions must be in slope intercept form which is y = mx+b. In this case, this step can be skipped because both functions are in slope form. At an intersection, x and y must have the same value for each equation. This means that the equations are equal to each other. Therefore, we can set both equations equal to each other to solve for x.
- Add x to both sides to get 2x - 1 = 3
- Add 1 to both sides to get 2x = 4
- Divide both sides by 2 to get x = 2
Step #2: We found the x-coordinate, but we need to find the y-coordinate. We know that the x-coordinate is 2, so substitute the number 2 into any of the given equations. So, either into y = 3 - x or y = x - 1.
The point of intersection is (2,1).
Hope this helps ^_^
