HCF of 12 and 15 by Prime Factorization
1. As visible, 12 and 15 have only one common prime factor i.e. 3. Hence, the HCF of 12 and 15 is 3.
2. To find the HCF of 20 and 25, we will find the prime factorization of the given numbers, i.e. 20 = 2 × 2 × 5; 25 = 5 × 5. ⇒ Since 5 is the only common prime factor of 20 and 25. Hence, HCF (20, 25) = 5.
We are asked to identify an another way to solve the given problem or this summation 104 + 34 + 228 + 887. We can verify it by doing of performing the summation in a reverse sequence such 877 comes first, then followed by 228, then followed by 34 and lastly added by 104. Therefore, the answer is 877 + 228 + 34 + 104.This is an another way to solve the given problem.
Hey!
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We know that (a = -3), (b = 2), (c = 5), and (d = -4).
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Solution #1:



≈ 1.57
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Solution #2:
= a - 4b / 3c + 2d
= (-3) - 4(2) / 3(5) + 2(-4)
= (-3) - 8 / 15 + (-8)
= (-3) - 0.53 + (-8)
= (-3.53) + (-8)
= -11.53
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Solution #1 Answer: 1.57
Solution #2 Answer: -11.53
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Answer:
It looks like it could be D.
Step-by-step explanation:
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