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3 years ago

A,B,C,D which one is right

Mathematics

2 answers:

ivanzaharov [21]3 years ago

6 0

C 16. Looking at the chart, there are 6 rows so just count 4 of the 6 rows

Vsevolod [243]3 years ago

4 0

Answer:

the answer is 8

because 24 divided by 3 is 8

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evaluate the expression 9(a 2b) c for a = –3, b = –2, and c = 1. i kept getting the answer of 10 but it's not one of my choices

den301095 [7]

What grade are u? I'm just asking cause the formulas are going with grade I could help if u want me too

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3 years ago

Find 3 consecutive even integers such that the sum of the three integers<br> is 90

sattari [20]

Step-by-step explanation:

29,30,31 is three consecutive interger that add up to 90

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2 years ago

Read 2 more answers

HURRY I NEED IT DONE FAST, LOTS OF POINTS, GIVING BRAINLIEST!!!

Ilia_Sergeevich [38]

Answer:

x = 2

Step-by-step explanation:

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2 years ago

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!!!!Please help!!! I am dying!!

stellarik [79]

Answer:

Therefore (x,y)=(3,7)

Step-by-step explanation:

put the second equation into the first

x+4=3x-2

x-3x=-2-4

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x=3

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6 0

11 months ago

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

1 year ago