What is not an input for a function?

Mathematics

2 answers:

likoan [24]3 years ago

4 0

The first box “3 divided by input”

Fed [463]3 years ago

3 0

The first box “3 divided by the imput”

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1. Mark charges $10 an hour to babysit with an additional flat fee of $20 for each babysitting job. He wants to purchase a new g

quester [9]

Answer:

Step-by-step explanation:

A.123.50≤20+10(x)

103.50≤10x

10.35 hours at least to equal the 123.50.

10.35 hours *10 an hour is 103.50+20 flat fee=123.50

B. 123.50≤15(x)

8.24 hours or more. 15.00 an hour at 8.24 hours = 123.60

C. He will work less hours if he charges more and does not charge the flat fee.

6 0

3 years ago

Read 2 more answers

Apply each of the four counting/sampling methods (with replacement and with ordering, without replacement and with ordering, wit

dusya [7]

Answer:

Step-by-step explanation:

I will illustrate this solution with a unique birthday party situation between Jane (the celebrant) and her 10 friends.

In the said party , we will assume that Jane only has 5 chocolates to share among her friends

i. Assuming that the 5 chocolates are of the same type, if she doesn't want to give any friend more than one piece of chocolate, the situation here is said to be WITHOUT REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

$(\left {n} \atop {k}} \right. )=(\left {10} \atop {5}} \right. )=252$

ii. Assuming that the 5 pieces of chocolate are of the same type and she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & UN-ORDERED

n = 10 and k = 5

Total number of possible combinations becomes,

$(\left {n+k-1} \atop {k}} \right. )=(\left {14} \atop {5}} \right. )=2002$

iii. Assuming that the 5 pieces of chocolate are of different types and she isn't willing to give any friend more than one piece of chocolate, the situation is said to be WITHOUT REPLACEMENT & ORDERED

n = 10 & k = 5

Total number of possible combinations becomes,

$P\left {n} \atop {k}} \right=P\left {10} \atop {5}} \right. =30240$

iv. Assuming the the 5 pieces of chocolate are of different types, if she is willing to give a friend more than one piece of chocolate, the situation is said to be WITH REPLACEMENT & ORDERED

n = 10 AND k = 5

Total number of combinations becomes

$n^k=10^5=100,000$