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Alborosie
4 years ago
11

Identify all values, if any, in the data set that would be considered outliers when creating a modified boxplot. 4 5 7 9 10 10 1

2 13 15 16 16 17 18 23 31
Mathematics
1 answer:
matrenka [14]4 years ago
5 0

Answer:

31

Step-by-step explanation:

 

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Kevin works 3z hours each day from Monday to Friday. He works (4z-7) on Saturday. Kevin does not work on Sunday. Find the number
marta [7]
During a week:
Kevin works 3z during 5 days
kevin work (4z-7) during 1 day.
Kevin work 0 during 1 day.

z=unit time
f(z)= number of hours kevin works in one week.

f(z)=5(3z)+(4z-7)+0
f(z)=15z+4z-7
f(z)=19z-7

The number of hours kevin woirs in one week in terms of z is:
f(z)=19z-7
6 0
3 years ago
6.  
EastWind [94]
The second question is biased
3 0
4 years ago
Read 2 more answers
Pat needs to paint an 8 ft x 36 ft rectangular wall. what is the area that she paints?
lora16 [44]

area = L x W

area = 8 x 36

area = 288 square feet

5 0
3 years ago
If a+b+c=2 , ab+bc+ac= -1 and abc = -2 , then find the value of a^3 + b^3 + c^3
grandymaker [24]

Answer:  8

<u>Step-by-step explanation:</u>

EQ1:   a + b + c = 2            -->       b + c = 2 - a

EQ2:  ab + bc + ac = -1     -->        b + c = (-1 - bc)/a

EQ3:  abc = -2                  -->           bc = -2/a

Set EQ1 = EQ2 and substitute bc using EQ3 to solve for "a":

2-a=\dfrac{-1-bc}{a}\\\\\\\text{Clear the denominator:}\\a(2-a)=-1-bc\\\\\text{Substitute bc:}\\a(2-a)=-1-\dfrac{-2}{a}\\\\\\\text{Clear the denominator:}\\a^2(2-a)=-a+2\\\\\\\text{Simplify and set equal to 0:}\\2a^2-a^3=-a+2\\0=a^3-2a^2-a+2\\\\\text{Factor:}\\0=a^2(a-2)-1(a-2)\\0=(a^2-1)(a-2)\\\\\text{Solve for a:}\\a^2-1=0\qquad a-2=0\\a=\pm1}\qquad \qquad  a=2

Consider the solution a = 2 and plug it into EQ1 to solve for "b"

b + c = 2 - 2

b + c = 0

b = -c

Plug in a = 2, b = -c, and c = c into a³ + b³ + c³

  2³ + (-c)³ + c³

= 8 - c³ + c³

= 8

4 0
4 years ago
Can y’all help me I know it’s easy but still 2×5.6÷2.8+3.5
Ipatiy [6.2K]

Answer:

7.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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